E2.4 - Fractional algebraic indices (Extended)

E2.4 - Fractional algebraic indices (Extended)

How can x1/3×x1/2x^{1/3}\times x^{1/2} be written as one power? Fractional indices let roots take part in the same index arithmetic as integer powers. This Extended E2.4 lesson develops products, quotients and nested rational powers, then solves common-base equations whose exponents contain the unknown.

Fractional powers

For a positive value of xx, x1/3x^{1/3} is its cube root and x1/2x^{1/2} is its positive square root. For example, when x=64x=64, these are 4 and 8. Their product is 32; a single rational power will describe that product for every positive xx.

Rational power

For x>0x>0 and integers m,nm,n with n>0n>0,

xm/n=(xn)m=xmn.x^{m/n}=(\sqrt[n]{x})^m=\sqrt[n]{x^m}.

A rational exponent represents a root and a power. Positive bases keep all rational powers real and make the index laws valid without sign ambiguities.

The equal-base multiplication law still adds the exponents. Add the fractions using a common denominator: 13+12=56\frac13+\frac12=\frac56, not 25\frac25. Coefficients multiply separately.

Products with rational indices

For x>0x>0 and rational r,sr,s,

xr×xs=xr+s.x^r\times x^s=x^{r+s}.

The bases must be equal before you add the indices.

Not on the supplied formula lists: learn the law.

Start with fractions that already have the same denominator, then change one exponent to require a common denominator.

Worked example 1: fractional powers combining to an integer

Question. Simplify 4x1/3×3x2/34x^{1/3}\times3x^{2/3}, for x>0x>0.

Plan. Multiply 4 by 3 and add the two fractional exponents.

4x1/3×3x2/3=12x1/3+2/3=12x1=12x\begin{aligned} 4x^{1/3}\times3x^{2/3} &=12x^{1/3+2/3}\\ &=12x^1=12x \end{aligned}

Answer. 12x12x.

Check. At x=64x=64, the original is 4(4)×3(16)=7684(4)\times3(16)=768. The result gives 12(64)=76812(64)=768. The cube root of xx and its square together contain three cube-root factors, whose product is xx.

Change only the second exponent from 23\frac23 to 12\frac12. The sum is no longer an integer, so keep it as a simplified rational exponent.

Worked example 2: different fractional denominators

Question. Simplify 4x1/3×3x1/24x^{1/3}\times3x^{1/2}, for x>0x>0.

Plan. Use denominator 6 to add the exponents.

4x1/3×3x1/2=12x2/6+3/6=12x5/6\begin{aligned} 4x^{1/3}\times3x^{1/2} &=12x^{2/6+3/6}\\ &=12x^{5/6} \end{aligned}

Answer. 12x5/612x^{5/6}.

Check. At x=64x=64, the original is 4(4)×3(8)=3844(4)\times3(8)=384. Since 64=2664=2^6, the result is 12(26)5/6=12(25)=38412(2^6)^{5/6}=12(2^5)=384.

The coefficient is not absorbed into the base: 4x1/34x^{1/3} means 4×x1/34\times x^{1/3}, whereas (4x)1/3(4x)^{1/3} takes the cube root of the complete product. Brackets distinguish them.

Watch out

In x1/3x1/2x^{1/3}x^{1/2}, add the fractions to get x5/6x^{5/6}. Multiplying the exponents would describe (x1/3)1/2(x^{1/3})^{1/2}, a different expression equal to x1/6x^{1/6}.

Keep the coefficient and exponent arithmetic separate.

Negative fractional powers

A negative fractional exponent combines two ideas: the fraction gives a root and power, and the minus gives a reciprocal. Thus x−1/2=1xx^{-1/2}=\frac1{\sqrt x}, for x>0x>0; it is not −x-\sqrt x.

Quotients and nested rational powers

For x>0x>0 and rational r,sr,s,

xrxs=xr−s,(xr)s=xrs,x−r=1xr.\frac{x^r}{x^s}=x^{r-s},\qquad (x^r)^s=x^{rs},\qquad x^{-r}=\frac1{x^r}.

For positive A,BA,B, (AB)r=ArBr(AB)^r=A^rB^r. The outside power applies to coefficients as well as variable powers.

Not on the supplied formula lists: learn these laws.

For example, x1/2÷x3/2=x−1=1xx^{1/2}\div x^{3/2}=x^{-1}=\frac1x. A surrounding square root then raises that whole result to power 12\frac12. Work from inside the brackets outwards to keep the two operations distinct.

Worked example 3: a quotient inside a root

Question. Simplify (9x1/2x3/2)1/2\left(\frac{9x^{1/2}}{x^{3/2}}\right)^{1/2}, for x>0x>0, giving positive indices.

Plan. Subtract the inner indices, then apply the outer power to both 9 and x−1x^{-1}.

(9x1/2x3/2)1/2=(9x−1)1/2inner index 12−32=−1=91/2x−1/2=3x1/2\begin{aligned} \left(\frac{9x^{1/2}}{x^{3/2}}\right)^{1/2} &=(9x^{-1})^{1/2} &&\text{inner index }\tfrac12-\tfrac32=-1\\ &=9^{1/2}x^{-1/2}\\ &=\frac3{x^{1/2}} \end{aligned}

Answer. 3x1/2\frac3{x^{1/2}}, or 3x\frac3{\sqrt x}.

Check. At x=4x=4, the inner quotient is 9(2)8=94\frac{9(2)}8=\frac94, whose positive square root is 32\frac32. The result is 34=32\frac3{\sqrt4}=\frac32.

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