C4.5; E4.5 - Parallel straight lines

C4.5; E4.5 - Parallel straight lines

Two straight tracks have equations y=2x+1y=2x+1 and y=2x−5y=2x-5. Can they ever meet? C4.5 and E4.5 connect parallel lines with equal gradients, then use a point to locate the particular parallel line you need.

Equal gradients

Increasing xx by 1 increases yy by 2 on both opening tracks. Their separation stays the same because neither line gains on the other.

Parallel straight lines

Distinct straight lines in the same plane are parallel if they never meet. Non-vertical parallel lines have the same gradient. Distinct vertical lines, such as x=1x=1 and x=4x=4, are also parallel, although their gradients are undefined.

For y=mx+cy=mx+c, compare the coefficients of xx, including their signs. Changing cc moves a line up or down without changing its gradient. Equal gradients with equal intercepts describe the same line, rather than two distinct parallel lines.

[DIAGRAM: asset_name: Equal gradients and different intercepts; asset_slug: parallel_equal_gradients; caption: Each line rises 2 units for a run of 1, while their vertical separation stays 6 units.; description: A coordinate grid shows the exact lines y equals 2x plus 1 and y equals 2x minus 5. Each has a labelled gradient triangle with run one and rise two. Their intercepts at one and minus five are marked on the y-axis and the equations label their corresponding lines.]
Each line rises 2 units for a run of 1, while their vertical separation stays 6 units.

Worked example 1: comparing gradients

Question. Are y=3x+2y=3x+2 and y=3x−4y=3x-4 parallel? Give a reason.

Plan. Read the two gradients and check that the equations describe different lines.

m1=3m2=3equal gradientsc1=2,c2=−4different intercepts\begin{aligned} m_1&=3\\ m_2&=3 &&\text{equal gradients}\\ c_1&=2,\quad c_2=-4 &&\text{different intercepts} \end{aligned}

Answer. Yes. They are distinct lines with the same gradient, 3.

Check. At x=0x=0 their outputs differ by 6. At x=2x=2 the outputs are 8 and 2, still differing by 6.

Only the sign of the second gradient changes next. Equal steepness alone does not give the same direction.

Worked example 2: a sign changes the decision

Question. Are y=3x+2y=3x+2 and y=−3x−4y=-3x-4 parallel? Give a reason.

Plan. Compare the signed gradients, rather than their sizes alone.

m1=3,m2=−3,3≠−3m_1=3,\qquad m_2=-3,\qquad 3\ne-3

The first line rises as xx increases; the second falls.

Answer. No. Their gradients are different.

Check. At x=−1x=-1, both equations give y=−1y=-1. The lines actually meet at (−1,−1)(-1,-1).

Horizontal lines have gradient zero: y=2y=2 and y=−6y=-6 are distinct parallel lines. Do not call a vertical line's gradient zero; its horizontal change is zero, so the gradient quotient is undefined.

Watch out

The intercept is not the gradient. The lines y=−2x+7y=-2x+7 and y=5x+7y=5x+7 share an intercept, so they meet at (0,7)(0,7); they are not parallel.

Use both gradient and distinctness in your explanation.

Parallel through a point

A gradient gives a family of parallel lines. A specified point selects one member of that family: copy the gradient into y=mx+cy=mx+c, then substitute both coordinates to find cc.

You already know

The point (a,b)(a,b) lies on y=mx+cy=mx+c exactly when b=ma+cb=ma+c. The first coordinate replaces xx, and the second replaces yy.

Keeping the gradient preserves direction. Finding the intercept makes the new line pass through the required point.

Worked example 3: a positive gradient

Question. Find the equation of the line parallel to y=2x+7y=2x+7 through (3,0)(3,0).

Plan. Use gradient 2, then substitute the point to find the new intercept.

y=2x+cparallel gradient0=2(3)+csubstitute (3,0)c=−6\begin{aligned} y&=2x+c &&\text{parallel gradient}\\ 0&=2(3)+c &&\text{substitute }(3,0)\\ c&=-6 \end{aligned}

Answer. y=2x−6y=2x-6.

Check. At x=3x=3, 2(3)−6=02(3)-6=0, so the point lies on the line. Its gradient is 2 and its intercept differs from 7.

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