E1.2 - Three sets and set relationships

E1.2 - Three sets and set relationships

Set notation can describe one element, a whole collection, or a relationship between collections. This Extended lesson develops E1.2 through membership and subset symbols, three-set Venn regions and sets defined by conditions, including coordinate pairs. You will distinguish these meanings before using them to organise more involved information.

Membership, subsets and the empty set

Is “33 belongs to AA” the same kind of statement as “every element of BB belongs to AA”? The first talks about one object; the second compares two complete collections. Their symbols need to preserve that distinction.

Let A={1,2,3,4}A=\{1,2,3,4\} and B={2,4}B=\{2,4\}. The number 22 is an element of AA. Both elements of BB are in AA, so the entire set BB fits inside AA.

Membership and subsets

x∈Ax\in A means “xx is an element of AA”; x∉Ax\notin A means it is not. For example, 3∈A3\in A and 5∉A5\notin A.

B⊆AB\subseteq A means “BB is a subset of AA”: every element of BB is in AA. Equality is allowed. B⊈AB\nsubseteq A means at least one element of BB is not in AA.

To disprove a subset claim, one counterexample suffices. For D={2,5}D=\{2,5\}, the element 55 shows D⊈AD\nsubseteq A; the fact that 22 is shared cannot rescue the claim. To prove a finite subset claim, check every element of the proposed subset.

[DIAGRAM: asset_name: Subsets and disjoint sets; asset_slug: extended_sets_relationships; caption: Containment and separation represent different relationships.; description: Two panels show universal rectangles. On the left, circle B lies entirely inside larger circle A, with elements 2 and 4 in B and 1 and 3 in A outside B. On the right, separate circles P and Q contain 1 and 3, and 2 and 4 respectively, with no overlap.]
Containment and separation represent different relationships.

The right-hand sets are disjoint: they have no common elements. Their intersection is the empty set, written ∅\varnothing, so P∩Q=∅P\cap Q=\varnothing and n(P∩Q)=0n(P\cap Q)=0. The set {0}\{0\} is different: it contains one element, zero. Empty braces {}\{\} also represent the empty set.

Every set is a subset of itself. The empty set is a subset of every set, because it has no element that could violate the condition “every element is in the other set”. That does not make it an element of every set: ∅∉{1,2}\varnothing\notin\{1,2\}, since the two elements are the numbers 11 and 22.

Key idea

Membership compares an object with a set. A subset statement checks whether an entire set fits inside another. For a set of numbers, 2∈A2\in A and {2}⊆A\{2\}\subseteq A express related facts using different kinds of object.

Check the kind of object on each side of the symbol in this question.

Three-set Venn regions

Three circles arranged with every kind of overlap produce eight separate regions, including the region outside all three. An element in all three belongs in the central overlap once. Begin there when totals include it, then move out to regions in exactly two sets and finally regions in only one.

Suppose a group has 4040 students. Sets A,B,CA,B,C contain 20,18,1720,18,17 students respectively. The counts in the pairwise intersections are n(A∩B)=8n(A\cap B)=8, n(A∩C)=7n(A\cap C)=7 and n(B∩C)=6n(B\cap C)=6, and 33 students belong to all three. Each given pairwise count includes the central three.

[DIAGRAM: asset_name: Eight regions of a three-set Venn diagram; asset_slug: extended_sets_three_regions; caption: Pairwise intersections include the central region unless “only” excludes it.; description: Three overlapping circles A, B and C lie in a universal rectangle of 40 students. Region counts are A only 8, B only 7, C only 7, A and B only 5, A and C only 4, B and C only 3, all three 3, and outside all three 3.]
Pairwise intersections include the central region unless “only” excludes it.

Worked example 1: separating inclusive pair counts

Question. For these students, find the number in A∩BA\cap B but not CC, and the number in AA only.

Plan. Subtract the central count from each needed pairwise total, then remove all other regions of AA from its total.

n(A∩B∩C′)=8−3=5exclude the central threen(A∩C∩B′)=7−3=4other pair-only region in AA only=20−(5+4+3)=8remove three occupied regions\begin{aligned} n(A\cap B\cap C')&=8-3=5 &&\text{exclude the central three}\\ n(A\cap C\cap B')&=7-3=4 &&\text{other pair-only region in }A\\ \text{A only}&=20-(5+4+3)=8 &&\text{remove three occupied regions} \end{aligned}

Answer. 55 belong to AA and BB only; 88 belong to AA only.

Check. 8+5+4+3=208+5+4+3=20, recovering the total for AA; 5+3=85+3=8, recovering the given A∩BA\cap B count.

Keep all counts and change the target to students outside every set. This requires the remaining regions, each counted once.

Continue this lesson.

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