5.10C - Calculating concentrations and volumes from titrations

5.10C - Calculating concentrations and volumes from titrations

A titration gives an accurate reacting volume: the volume of one solution needed to exactly react with a fixed volume of another solution. In this lesson, you use those results to calculate either an unknown concentration or an unknown volume required. This separate Chemistry point is Higher tier only. Follow the balanced-equation ratio as well as the concentration and volume units.

What a titration result tells you

In an acid-alkali titration, a measured volume of one solution is placed in a conical flask using a pipette. The other solution is added from a burette until the indicator shows the end point. The titre is the volume delivered from the burette.

Concordant titres are accurate titres within the stated tolerance. Exclude the rough trial and any result outside that close group, then add the selected titres and divide by their number.

For calculation questions, the experimental method is usually already done. Your job is to use the useful result, usually a mean titre from concordant accurate titres, rather than a rough trial.

Titre

The titre is the volume of solution added from the burette to reach the end point in a titration.

A titration calculation always depends on the balanced equation. If the equation shows a 1:1 ratio, the reacting amounts in moles are equal. If the equation shows a 1:2 ratio, one substance reacts with twice as many moles of the other substance.

For example:

Balanced equationMole ratio used in the calculation
HCl+NaOH→NaCl+HX2O\ce{HCl + NaOH -> NaCl + H2O}1 mol HCl reacts with 1 mol NaOH
HX2SOX4+2 NaOH→NaX2SOX4+2 HX2O\ce{H2SO4 + 2NaOH -> Na2SO4 + 2H2O}1 mol H2SO4 reacts with 2 mol NaOH

Relationships and units

The main relationship is the same concentration relationship used for solutions:

Moles in a solution

n=c×Vn = c \times V

where:

SymbolMeaningUnit needed in this relationship
namount of substancemol
cconcentrationmol dm^-3
Vvolumedm^3

Titration volumes are usually measured in cm3\mathrm{cm}^{3}, but the calculation needs dm3\mathrm{dm}^{3}.

Volume conversion

V in dm3=V in cm31000V\text{ in dm}^3 = \frac{V\text{ in cm}^3}{1000}

So 25.0 cm3=0.0250 dm325.0\,\mathrm{cm}^{3} = 0.0250\,\mathrm{dm}^{3} and 18.65 cm3=0.01865 dm318.65\,\mathrm{cm}^{3} = 0.01865\,\mathrm{dm}^{3}.

You may also need rearranged forms:

UnknownRelationship to use
molesn=c×Vn = c \times V
concentrationc=n/Vc = n / V
volumeV=n/cV = n / c

Use the full calculator value through the working. Round only at the final answer, unless the question asks for a particular number of significant figures or decimal places.

Calculation route

Most titration calculations follow the same route. Start with the solution where both the concentration and the reacting volume are known. Use n=c×Vn = c \times V to calculate its moles. Then use the mole ratio from the balanced equation to find the moles of the unknown solution.

[DIAGRAM: titration_calculation_route: Titration calculation route - diagram 1; asset_slug: 129_5_10c_titration_calculations_for_unknown_concentration_or_volume_diagram1; file: diagram_assets/129_5_10c_titration_calculations_for_unknown_concentration_or_volume_diagram1.png; recommended_method: deterministic_drawn; description: Monochrome flow diagram showing how titration results lead from mean titre, cm3 to dm3 conversion, known solution moles using n = c x V, balanced-equation mole ratio, then either c = n / V for unknown concentration or V = n / c for unknown volume. Assessed/exact calculation route; all formulae are also explained in nearby prose for accessibility.]
Diagram

A reliable written method is:

  1. Write or use the balanced equation.
  2. Convert any volume in cm3\mathrm{cm}^{3} into dm3\mathrm{dm}^{3}.
  3. Calculate moles of the solution with known concentration and known volume.
  4. Use the mole ratio to find moles of the other solution.
  5. Calculate the unknown concentration using c=n/Vc = n / V, or the unknown volume using V=n/cV = n / c.
  6. Give the final answer with the correct unit.

Do not use c1 V1=c2 V2c_{1}\,\mathrm{V}_{1} = c_{2}\,\mathrm{V}_{2} automatically. It only works directly for a 1:1 reaction; the safer Edexcel method is to go through moles and the balanced-equation ratio.

Edexcel calculation habits

For Calculate questions, show enough working that the method can be followed. A correct final answer may gain credit, but clear working protects you if you make one arithmetic slip because later correct steps can often be credited using error carried forward.

Strong titration calculation answers usually include:

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