7.01b, 7.01d - Exponential graphs

7.01b, 7.01d - Exponential graphs

A graph can keep falling without ever reaching zero. In 7.01b you will plot exponential values, then in 7.01d you will recognise growth, decay and the special case between them. These are Higher-tier graph skills.

Plotting exponential values

If a quantity halves each time you move one unit to the right, will its graph ever cross the horizontal axis? Start by plotting a simpler multiplier: doubling.

For y=2xy=2^x, the variable is the exponent. The base 22 stays fixed. This differs from y=x2y=x^2, where the variable is the base. Negative powers give reciprocals: 2−2=1/22=1/42^{-2}=1/2^2=1/4, not −4-4.

Exponential graph

An exponential graph has the variable in the exponent, such as y=2xy=2^x or y=3×1.1xy=3\times1.1^x. We use a positive base so that the graph is defined for every real xx.

A table gives accurately placed points. Choose scales that include the largest value, plot each coordinate, and draw a smooth curve through the points. Integer inputs are sampling points: the graph also contains values between them.

Worked example 1: plotting powers of two

Question. Complete a table and plot y=2xy=2^x for −2≤x≤2-2\le x\le2.

Plan. Evaluate the powers, then plot the ordered pairs on suitable axes.

2−2=14reciprocal of 222−1=12reciprocal of 220=1zero power21=2,22=4positive powers\begin{aligned} 2^{-2}&=\tfrac14 &&\text{reciprocal of }2^2\\ 2^{-1}&=\tfrac12 &&\text{reciprocal of }2\\ 2^0&=1 &&\text{zero power}\\ 2^1&=2,\quad 2^2=4 &&\text{positive powers} \end{aligned}
xx−2-2−1-1001122
yy0.250.250.50.5112244

Answer. Plot (−2,0.25)(-2,0.25), (−1,0.5)(-1,0.5), (0,1)(0,1), (1,2)(1,2), (2,4)(2,4) and join with a smooth increasing curve.

Check. Each one-unit increase in xx doubles yy, including 0.50.5 to 11. The changes in yy are not equal, so a straight line would be wrong.

Now change only the multiplier outside the power. Calculate the power before multiplying.

Worked example 2: a multiplier before the power

Question. Complete a table and plot y=3×2xy=3\times2^x over the same interval.

Plan. Multiply each value from the previous table by 33.

3×2−2=3×14=0.75power first3×20=3×1=3the vertical intercept3×22=3×4=12right-hand endpoint\begin{aligned} 3\times2^{-2}&=3\times\tfrac14=0.75 &&\text{power first}\\ 3\times2^0&=3\times1=3 &&\text{the vertical intercept}\\ 3\times2^2&=3\times4=12 &&\text{right-hand endpoint} \end{aligned}
xx−2-2−1-1001122
yy0.750.751.51.533661212

Answer. Plot these five coordinates with a vertical scale reaching 1212, then draw a smooth increasing curve.

Check. The outputs still double for each unit step. At x=1x=1, direct substitution gives 3×2=63\times2=6, agreeing with the table.

The two plots show the same repeated-multiplication pattern at different heights.

[DIAGRAM: asset_name: Plotting two exponential tables; asset_slug: exponential-tables; caption: Accurate table points lie on smooth curves, with vertical intercepts one and three.; description: Two coordinate plots show y equals two to the power x and y equals three times two to the power x from x negative two to two. All five integer-input table points are marked on each curve.]
Accurate table points lie on smooth curves, with vertical intercepts one and three.

For a decimal base, such as 1.11.1, use the same procedure with a calculator. Keep sufficient digits when calculating, then plot to the precision the grid allows.

Watch out

3×2x3\times2^x is not 6x6^x. At x=0x=0, the first gives 33, while the second gives 11. Brackets and the position of the exponent matter.

Apply the table method to a fresh multiplier.

Growth and decay graph shapes

The base decides whether the positive outputs grow or decay as you move to the right.

Compare 1,3,91,3,9 with 1,1/3,1/91,1/3,1/9. The first repeatedly multiplies by 33, and the second by 1/31/3. For y=kxy=k^x, increasing xx by one multiplies the output by kk, because kx+1=k×kxk^{x+1}=k\times k^x.

Key idea

For y=kxy=k^x, if k>1k>1 the curve increases. If 0<k<10<k<1 it decreases. Both have vertical intercept (0,1)(0,1), positive outputs and no horizontal-axis intercept.

The xx-axis is a horizontal asymptote for these nonconstant curves: the graph gets arbitrarily close to it in one direction without reaching it. Growth approaches zero far to the left; decay approaches zero far to the right.

Worked example 3: recognising growth

Question. Sketch y=3xy=3^x, labelling the intercept and two other points. Describe its behaviour as xx increases.

Plan. Use three easy powers to anchor the shape, then apply repeated multiplication.

3−1=13point left of the axis30=1vertical intercept31=3point right of the axis\begin{aligned} 3^{-1}&=\tfrac13 &&\text{point left of the axis}\\ 3^0&=1 &&\text{vertical intercept}\\ 3^1&=3 &&\text{point right of the axis} \end{aligned}

Answer. Draw a smooth increasing curve through (−1,1/3)(-1,1/3), (0,1)(0,1), (1,3)(1,3). It remains above the xx-axis, approaches it to the left, and grows without bound to the right.

Check. Moving from x=−1x=-1 to 00 to 11 triples the output each time. This checks the direction of growth.

Continue this lesson.

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