5.1.1(i) - Rate-determining step

5.1.1(i) - Rate-determining step

A rate equation is more than a calculation tool: it is experimental evidence about the pathway of a reaction. In this lesson you will use the rate-determining step to connect a multi-step mechanism with the observed rate equation, then work backwards from a rate equation and overall equation to suggest possible mechanism steps.

Slow Step Evidence

Many reactions do not happen in one collision. They happen through a sequence of elementary steps, and the slowest step controls the overall rate in the same way that the narrowest point of a route controls the flow through the whole route.

Rate-determining Step

The rate-determining step is the slowest step in a multi-step reaction mechanism. It controls the rate of the overall reaction.

The key OCR idea is evidence-based: a rate equation is found experimentally, then used to test whether a proposed mechanism is consistent with the evidence. You cannot usually predict the rate equation from the balanced overall equation alone.

For a simple elementary slow step, the species taking part in that slow step appear in the rate equation. If one particle of AA and one particle of BB collide in the slow step, the rate equation is first order with respect to AA and first order with respect to BB:

slow step: A+B→products\text{slow step: } A+B \rightarrow \text{products} rate=k[A][B]\text{rate}=k[A][B]

If two particles of the same species take part in the slow step, that species appears squared:

slow step: 2A→products\text{slow step: } 2A \rightarrow \text{products} rate=k[A]2\text{rate}=k[A]^2

A reactant that only appears after the slow step does not control the rate in this simple OCR reasoning. It may be in the overall equation, but absent from the rate equation.

Worked reasoning: suppose a proposed mechanism has this slow step:

X(aq)+2Y(aq)→Z(aq)X(aq)+2Y(aq)\rightarrow Z(aq)

The slow step involves one XX and two YY particles, so the predicted rate equation is:

rate=k[X][Y]2\text{rate}=k[X][Y]^2

The rate equation does not include ZZ, because ZZ is a product of the slow step rather than a reactant in that step.

Predicting Rate Equations

When the slow step is given, work from the reactants in that step, not from the whole equation. The overall equation tells you what changes from start to finish; the slow step tells you which collision or rearrangement limits the rate.

Worked example: nitrogen dioxide and carbon monoxide

The overall reaction is:

NOX2(g)+CO(g)→NO(g)+COX2(g)\ce{NO2(g) + CO(g) -> NO(g) + CO2(g)}

A possible two-step mechanism is:

NOX2(g)+NOX2(g)→NOX3(g)+NO(g)slow\ce{NO2(g) + NO2(g) -> NO3(g) + NO(g)}\quad \text{slow} NOX3(g)+CO(g)→NOX2(g)+COX2(g)fast\ce{NO3(g) + CO(g) -> NO2(g) + CO2(g)}\quad \text{fast}

The slow step contains two NOX2\ce{NO2} molecules and no CO\ce{CO} molecule. The predicted rate equation is therefore:

rate=k[NOX2]2\text{rate}=k[\ce{NO2}]^2

This does not mean CO\ce{CO} is unreactive. It means CO\ce{CO} is used in a later fast step, so changing the concentration of CO\ce{CO} does not affect the rate in this proposed mechanism.

Check that the steps really add to the overall equation:

NOX2+NOX2→NOX3+NONOX3+CO→NOX2+COX2\begin{aligned} \ce{NO2 + NO2}&\ce{->}\ce{NO3 + NO}\\ \ce{NO3 + CO}&\ce{->}\ce{NO2 + CO2} \end{aligned}

Cancel NOX3\ce{NO3}, because it is made in one step and used in another. Cancel one NOX2\ce{NO2}, because it appears on both sides. The remaining equation is:

NOX2+CO→NO+COX2\ce{NO2 + CO -> NO + CO2}

That matches the overall equation.

For this OCR skill, a proposed mechanism must pass two tests: the slow step must match the rate equation, and all the steps must add up to the balanced overall equation.

Building Possible Mechanisms

OCR can also ask the reverse question: given the experimental rate equation and the balanced overall equation, suggest possible steps in the mechanism.

Use this route:

  1. Start the slow step with the species shown in the rate equation.
  2. For a proposed first elementary slow step, use the powers as its reactant particle counts. If a fast step precedes it, check how that earlier step relates the intermediate concentration to measured reactants; do not infer that relation merely from the intermediate's origin.
  3. Create an intermediate if the slow step cannot directly make the final products.
  4. Add one or more fast steps so that all steps add up to the overall equation.
  5. Check atoms, charge and cancellation.

Continue this lesson.

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