3.1.12.3 - The Ionic Product of Water, Kw

3.1.12.3 - The Ionic Product of Water, Kw

This lesson is about the tiny extent to which water dissociates and why that tiny change still matters in acid-base chemistry. Even pure water is quietly producing a few ions all the time. You will see where KwK_w comes from, why its value changes with temperature, and how to use it to calculate the pH of a strong base from its concentration.

Water dissociation and the meaning of Kw

Pure water is not made of only uncharged molecules. A very small fraction of water molecules dissociate at any moment, so pure water contains both hydrogen ions and hydroxide ions:

H2O(l)⇌H+(aq)+OH−(aq)\mathrm{H_2O(l) \rightleftharpoons H^+(aq) + OH^-(aq)}

Because this dissociation is only slight, most of the particles are still HX2O(l)\ce{H2O(l)}. That is why water is described as slightly dissociated.

Ionic product of water, Kw

The ionic product of water, KwK_w, is the equilibrium constant for the dissociation of water after the constant concentration of liquid water has been incorporated into the constant. At a fixed temperature, Kw=[HX+][OHX−]K_w = [\ce{H^+}][\ce{OH^-}].

To see where that expression comes from, start with the equilibrium constant for the dissociation of water:

Kc=[H+][OH−][H2O]K_c = \frac{[\mathrm{H^+}][\mathrm{OH^-}]}{[\mathrm{H_2O}]}

In this equilibrium, water is a pure liquid, so its concentration is effectively constant. Chemists therefore combine [HX2O]\ce{[H2O]} with KcK_c to make a new constant:

Kw=Kc[H2O]K_w = K_c[\mathrm{H_2O}]

Ionic product of water

Kw=[H+][OH−]Kw=1.00×10−14 mol2 dm−6 at 298 KK_w = [\mathrm{H^+}][\mathrm{OH^-}] \qquad K_w = 1.00 \times 10^{-14}\,\mathrm{mol^2\,dm^{-6}} \text{ at } 298\,\mathrm{K}

At 25 °C, the value of KwK_w is 1.00×10−14 mol2 dm−61.00 \times 10^{-14}\,\mathrm{mol}^{2}\, \mathrm{dm}^{-6}. In pure water, the concentrations of HX+\ce{H+} and OHX−\ce{OH-} are equal, so each one must be 1.00×10−7 mol dm−31.00 \times 10^{-7}\,\mathrm{mol}\, \mathrm{dm}^{-3}.

At a fixed temperature this ionic-product relationship applies to acidic and alkaline aqueous solutions as well as pure water. Adding acid raises [HX+][\ce{H+}], so [OHX−][\ce{OH-}] decreases but does not become zero. Neutrality means equal concentrations of these two ions; pH 7 is the neutral value specifically at about 25 ∘C25\,^{\circ}\mathrm C.

Why Kw changes with temperature

KwK_w is not one fixed number for all temperatures. The forward dissociation of water is endothermic, so increasing the temperature favours the forward reaction.

The diagram below summarises how the endothermic forward reaction leads to larger ion concentrations and a larger KwK_w at higher temperature.

[DIAGRAM: asset_name: 1.12.3 - The Ionic Product of Water, Kw - Diagram 1; asset_slug: 1.12.3 - The Ionic Product of Water, Kw - Diagram 1; recommended_method: matplotlib_exact_plot; description: Neutral water at10,25,40 Celsius; Kw2.93e-15,1e-14,2.92e-14; neutral pH7.27,7.00,6.77; equal-ion neutrality and temperature effect.]
Diagram
That means both [HX+][\ce{H+}] and [OHX−][\ce{OH-}] increase as temperature rises, so the product [HX+][OHX−][\ce{H+}][\ce{OH-}] increases too. Therefore KwK_w increases when temperature increases.

Neutral

A neutral solution has equal concentrations of HX+\ce{H+} ions and OHX−\ce{OH-} ions.

Hotter pure water does not become acidic. In pure water, the concentrations of HX+\ce{H+} and OHX−\ce{OH-} increase together, so they remain equal. The pH of neutral water becomes lower than 7 at higher temperature, but the water is still neutral because [HX+]=[OHX−][\ce{H+}] = [\ce{OH^-}].

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