Use of data in statistics - Large Data Set weather data
Pearson's Large Data Set turns statistical calculations into questions about real weather. You will learn its places, periods, variables and recording codes, make sensible cleaning and sampling decisions, and investigate an actual comparison between Heathrow in 1987 and 2015.
Why the Large Data Set matters
Was Heathrow warmer in 2015 than in 1987, or does the answer depend on the month you choose? In the official data, the daily mean temperatures on 1 June were in 1987 and in 2015. That one day favours 1987. Before making a claim about a month or a year, we need a better question and more of the data.
You already know
A mean uses the total divided by the number of observations. A graph can reveal a pattern that one observation hides. A conclusion must describe the observations you actually used.
Pearson supplies this weather dataset for the Statistics section of Paper 3. An examination question may give an extract, a diagram or summary statistics and assume that you already understand the weather context. Familiarity lets you spend your time interpreting the evidence rather than decoding a heading.
Large Data Set familiarity
Knowing the dataset's locations, periods, variable meanings, units and special codes, and using that knowledge to interpret a statistical result. It does not mean memorising individual daily observations.
You do not need a copy of the spreadsheet in the examination and are not required to memorise detailed raw values. During the course, however, explore the actual spreadsheet with a calculator, spreadsheet or statistical software. Select data, clean it, plot it and check the summaries: reading a list of headings is only the start.
Key idea
Learn what a value means and which claim it can support; the raw number alone cannot supply its context.
For example, a printed rainfall extract still needs a reader who recognises the code tr and knows that the entries are daily totals in millimetres.
Places, periods and the population represented
The data are Met Office weather records for eight stations, covering May to October in 1987 and the same months in 2015.
| UK stations | Overseas stations |
|---|---|
| Camborne | Beijing |
| Heathrow | Jacksonville |
| Hurn | Perth |
| Leeming | |
| Leuchars |
Here is a useful surprise: the workbook contains station-day rows, since . Yet it contains no November observations at all. A large row count cannot repair a gap in the calendar.
Target population
The complete set of observations about which you want to draw a conclusion. For example, all daily mean temperatures at Leeming during 2015 form one target population. The May-to-October records cover only part of it; they are not the whole year's weather.
Specify the variable, place and time. “Weather at Leeming” leaves too much open. If the target is all May-to-October days at Leeming in 2015, the workbook covers that period. If the target is all days in 2015, November to April are absent. If the target is long-term climate, two selected years are a further limitation.
Using Leeming's May-to-October temperatures to estimate its annual mean is likely to overestimate it because the colder winter months are omitted. Location changes interpretation too: July is a winter month in Perth, in the southern hemisphere, and a summer month at the UK stations. Coastal setting, latitude and urban surroundings may help explain patterns, but they do not replace evidence.
Key idea
Always name the variable, station and period before deciding whether the data represent your target population.
The same observations can be the whole population for one narrow question and a sample from a broader population for another.
Weather variables and units
A daily rainfall total of is a depth of precipitation, not the number of hours during which it rained. Read the heading before touching the calculator.
| Variable | Unit or recording convention | Coverage |
|---|---|---|
| Daily mean temperature | degrees Celsius, | UK and overseas |
| Daily total rainfall | millimetres, | UK and overseas |
| Daily mean pressure | hectopascals, | UK and overseas |
| Daily mean windspeed | knots, , with a Beaufort category | UK and overseas |
| Daily total sunshine | hours | UK |
| Daily maximum relative humidity | percentage, | UK |
| Daily mean visibility | decametres, | UK |
| Daily mean total cloud | oktas, or eighths of the sky | UK |
| Daily maximum gust | knots, | UK |
| Mean-wind and maximum-gust directions | degrees, with cardinal directions | UK |
Weather recording conventions
One decametre is , so a visibility of is . Cloud cover is recorded in eighths: oktas means clear sky and means complete cloud cover. Wind direction names where the wind comes from: , or west, means wind coming from the west.
Daily totals and daily means also use particular recording periods. The Information sheet defines daily rainfall over the hours starting at 0900 GMT on the date of entry, whereas daily mean windspeed uses the hours starting at 0000 GMT. A date does not guarantee that every variable covers exactly the same interval. Temperature is the mean of hourly readings over 0900–0900 GMT; it is not defined here as the mean of the daily maximum and minimum.
A mean or standard deviation of windspeed is measured in knots, just as the original observations are. A correlation coefficient has no units. Later, a regression gradient for rainfall against sunshine has units per hour of sunshine: dividing one variable by another changes the units. These dataset conventions are not supplied as a list in the formula booklet; learn them through use.
Watch out
Wrong: “The visibility is ” when the entry is . The heading uses decametres, so multiply by : the visibility is .
Units can expose a wrong interpretation even when the arithmetic looks tidy.
Cleaning codes and unusual values
An empty measurement and a tiny measurement are different things. Cleaning means recording defensible decisions before calculation, not changing inconvenient observations until a pattern appears.
Missing and trace observations
n/a means that a reading is not available; it does not mean zero. The Information sheet also describes a dash as unavailable visibility data. For rainfall, tr means a trace: a small positive amount less than . If its true value is , then .
Follow any cleaning convention given in a question. Otherwise, state your treatment. Omitting a missing value reduces the usable count for calculations involving that variable. For a numerical rainfall calculation, a stated approximation such as for each trace is defensible; it gives an estimate, not the exact unrecorded rainfall. Rounding a trace to zero can also be a stated approximation, but calling a trace exactly zero is false.
Worked example 1: a missing observation is not a dry day
Question. An invented miniature rainfall extract is , tr, , n/a, in millimetres. Estimate its mean rainfall using for tr and omitting the unavailable reading.
Plan. Replace only the trace code, count the usable observations, then divide their total by that count.
Why this step? Dividing by would treat the missing reading as an additional observed dry day.
Answer. The estimated mean is , to significant figures, based on usable readings.
Check. The estimate lies between and . The unavailable day could have been wet or dry, so this is not a mean for all four days.
Change one feature: the unavailable reading is now an observed zero. This changes the denominator even though it does not add to the total.
Worked example 2: an observed dry day stays in the count
Question. An invented miniature rainfall extract is , tr, , , in millimetres. Estimate its mean using for tr.
Plan. Keep all four recorded readings, replace tr by the stated approximation, and divide by .
Why this step? A real zero contributes to the count; n/a did not provide an observation to count.
Answer. The estimated mean is , to significant figures.
Check. The same estimated total is spread over more observed days, so the mean is smaller than in Worked example 1.
An extreme but physically possible reading stays unless there is evidence of an error. Check the station, units and neighbouring records; a wet day is not a typing mistake simply because it raises the mean.
Watch out
Wrong: “Replace both n/a and tr by zero.” The first is missing and the second represents positive rainfall. Record separate treatments and the resulting usable count.
Keep enough detail in your cleaning notes for someone else to reproduce the calculation.
Sampling and fair comparison
Comparing May 1987 with September 2015 changes two things at once: the year and the season. A difference cannot then be attributed to the year alone.
Comparable weather samples
Samples chosen so that differences irrelevant to the question are controlled as far as possible. For a comparison of years at one station, use the same variables, units and months in both years. Matching months reduces seasonal imbalance; it does not make two years sufficient for a long-term climate claim.
First define the target, then choose eligible days. A simple random sample gives every possible sample of the chosen size the same chance of selection. Select without replacement from a complete list of eligible dates. A block of consecutive dates is not a simple random sample: weather systems can persist, so neighbouring observations may also be related. Later sampling lessons develop the selection methods in detail.
Worked example 3: repairing a seasonally unbalanced comparison
Question. A student wants to compare mean temperatures at Heathrow over May to October in 1987 and 2015. The student chooses random May days in 1987 and random September days in 2015. Criticise the design and describe a better one.
Plan. Compare the target with the actual months represented, then propose the same month coverage in both years.
- The first sample represents May and the second September: season is mixed up with year.
- Neither single month represents the full May-to-October target.
- Use six month groups in each year and select dates randomly without replacement from each group.
Why this step? Giving both years the same month coverage prevents one year being represented mostly by cooler months.
Answer. The original comparison is seasonally unbalanced. The proposed design uses days in each year with equal month coverage. Equal numbers per month make a simple balanced comparison; they do not give exactly proportional allocation to months of different lengths.
Check. Each recorded month appears in both samples, and every selection is from dates in the intended year and station.
Change one feature: both original samples now come from May. Seasonal imbalance between the two samples disappears, but the target still covers six months.
Continue this lesson.
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