A22 - Solving linear inequalities

A22 - Solving linear inequalities

An inequality can have a whole range of answers. You will solve linear inequalities, show their solutions on number lines, and decide which whole-number values are allowed. Most steps work like solving equations, with one important change when you multiply or divide by a negative number.

Reading a solution set on a number line

A lift can carry at most 600 kg600\,\mathrm{kg}. Its passengers and luggage already have mass 420 kg420\,\mathrm{kg}. How much more mass can go in? Is the boundary amount allowed? An inequality gives both the limit and the answer to that last question.

You already know

x<3x<3 means xx is less than 33; x⩽3x\leqslant3 includes 33. Likewise, >> means greater than and ⩾\geqslant means greater than or equal to. Values increase as you move right on a number line.

For x>2x>2, numbers such as 2.12.1, 33 and 100100 work, but 22 itself does not. For x⩾2x\geqslant2, the boundary 22 works as well. Both include decimals and fractions unless a question restricts xx to integers.

Solution set and boundary

The solution set contains every value that makes an inequality true. A boundary separates allowed from disallowed values. A strict inequality, << or >>, excludes its boundary. An inclusive inequality, ⩽\leqslant or ⩾\geqslant, includes it.

On a number line, use an open circle for an excluded boundary and a filled circle for an included boundary. An arrow shows that the solution continues without an end in that direction. A segment between two boundary circles shows a bounded range.

[DIAGRAM: asset_name: Open and filled boundary circles; asset_slug: aqa8300_a12_number_lines; caption: The circle decides whether an endpoint belongs to the solution; the line decides which values belong; description: Three number lines. Top x greater than 2 has an open circle at 2 and a right arrow. Middle x greater than or equal to 2 has a filled circle at 2 and a right arrow. Bottom minus 1 less than x less than or equal to 3 has an open circle at minus 1, a filled circle at 3 and a coloured segment between them.]
The circle decides whether an endpoint belongs to the solution

The bottom line means −1<x-1<x and x⩽3x\leqslant3, written together as −1<x⩽3-1<x\leqslant3. The numbers are in increasing order. These number-line conventions are not on the formulae sheet: learn them.

There are infinitely many solutions between 22 and 33, although there is no integer strictly between them. For example, 2.52.5, 2.252.25, 2.1252.125 and the continuing pattern all lie there. Between any two different numbers you can choose their midpoint, so you cannot run out of numbers to insert.

Key idea

A solution is usually a range of values, not just its boundary. Read both the circle and the direction or segment.

Check an excluded endpoint carefully in the following question.

Solving with addition and positive division

You can add or subtract the same number on both sides of an inequality without changing its direction. Multiplying or dividing by the same positive number also keeps the direction. These operations preserve the order of the values on a number line.

Start with 2<52<5. Adding 44 gives 6<96<9. Dividing both original numbers by 22 gives 1<2.51<2.5. Neither operation reverses which is smaller.

Operations that keep the direction

For a positive number cc,

a<b⟹a+k<b+ka<b⟹ac<bc\begin{aligned} a<b&\Longrightarrow a+k<b+k\\ a<b&\Longrightarrow \frac ac<\frac bc \end{aligned}

The same principles apply to >>, ⩽\leqslant and ⩾\geqslant. Subtraction is addition of a negative number.

Not on the formulae sheet: learn it.

These non-calculator examples undo an addition, then a positive multiplication. Keep an inequality sign in every line.

Worked example 1: a strict inequality

Question. Solve 3x+4<193x+4<19. Describe its number-line representation.

Plan. Subtract 44, then divide by the positive coefficient 33.

3x+4<19start with the inequality3x<15subtract 4 from both sidesx<5divide both sides by 3\begin{aligned} 3x+4&<19 && \text{start with the inequality}\\ 3x&<15 && \text{subtract }4\text{ from both sides}\\ x&<5 && \text{divide both sides by }3 \end{aligned}

Why this step? Positive division preserves order, so the sign stays <<.

Answer. x<5x<5: an open circle at 55 with an arrow to the left.

Check. x=4x=4 gives 16<1916<19, true; x=5x=5 gives 19<1919<19, false. The boundary is correctly excluded.

Change only the sign to an inclusive one. The boundary calculation stays the same, but the boundary is now allowed.

Worked example 2: including the boundary

Question. Solve 3x+4⩽193x+4\leqslant19. Describe its number-line representation.

Plan. Use the same inverse operations while keeping the inclusive sign.

3x+4⩽19given inequality3x⩽15subtract 4x⩽5divide by positive 3\begin{aligned} 3x+4&\leqslant19 && \text{given inequality}\\ 3x&\leqslant15 && \text{subtract }4\\ x&\leqslant5 && \text{divide by positive }3 \end{aligned}

Why this step? Equality was allowed at the start, so it remains allowed after the same operations on both sides.

Answer. x⩽5x\leqslant5: a filled circle at 55 with an arrow to the left.

Check. At x=5x=5, the original gives 19⩽1919\leqslant19, true. At x=6x=6, it gives 22⩽1922\leqslant19, false.

Solving the corresponding equation finds the boundary. It does not tell you which side of it is allowed unless you retain the inequality.

Watch out

Wrong: replacing 3x+4<193x+4<19 by 3x+4=193x+4=19, then answering x=5x=5. That is the excluded boundary. Right: preserve the sign and answer x<5x<5.

Use the same steps with a new coefficient and boundary.

Continue this lesson.

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