A12 - Cubic, reciprocal and exponential graphs

A12 - Cubic, reciprocal and exponential graphs

Some curves pass through the origin; others get close to an axis without ever reaching it. In A12 you will recognise, sketch and interpret simple cubic and reciprocal graphs. The Higher part adds exponential graphs, whose equal steps multiply the height instead of adding to it.

Recognising and sketching cubic graphs

Can a smooth graph get closer and closer to both axes without ever touching either? A reciprocal graph can. First compare it with a cubic, which goes straight through the origin.

You already know

Substitute an input into a rule to find its output. A graph consists of the points (x,y)(x,y) that satisfy the rule. Put a negative input in brackets before raising it to a power.

For y=x3y=x^3, the inputs −2,−1,0,1,2-2,-1,0,1,2 give heights −8,−1,0,1,8-8,-1,0,1,8. Unlike squaring, cubing keeps a negative input negative: (−2)3=(−2)(−2)(−2)=−8(-2)^3=(-2)(-2)(-2)=-8. The curve rises from bottom left to top right. It flattens at the origin but keeps rising through it; the origin is not a maximum or minimum.

Cubic function

A function whose highest power of xx is 33, such as y=x3y=x^3 or y=x3−xy=x^3-x. The coefficient of x3x^3 must be non-zero. For example, y=2x3+1y=2x^3+1 is cubic; y=3x2+1y=3x^2+1 is quadratic.

The basic cubic's shape and its value rule are not on the formulae sheet: learn them. A sketch shows the overall shape, crossings and important points. An accurately plotted graph also uses a consistent scale and calculated coordinates. Draw a smooth curve in either case.

Worked example 1: the basic cubic

Question. Complete a table for y=x3y=x^3 at x=−2,−1,0,1,2x=-2,-1,0,1,2. Describe the sketch and its axis crossings. Non-calculator.

Plan. Cube each whole input, then use the signs and the zero value to describe the curve.

(−2)3=−8three negative factors(−1)3=−1three negative factors03=0the origin13=1,23=8positive cubes\begin{aligned} (-2)^3&=-8 &&\text{three negative factors}\\ (-1)^3&=-1 &&\text{three negative factors}\\ 0^3&=0 &&\text{the origin}\\ 1^3&=1,\quad 2^3=8 &&\text{positive cubes} \end{aligned}
xx−2-2−1-1001122
yy−8-8−1-1001188

Why this step? The opposite signs on either side of zero tell you that the curve crosses the axis, rather than turning back at it.

Answer. A smooth rising S-shaped curve through the five points. It crosses both axes at (0,0)(0,0).

Check. Opposite inputs give opposite outputs: (−2,−8)(-2,-8) pairs with (2,8)(2,8).

Change only the coefficient of the cubic term from 11 to −1-1. Cube first, then apply the outside minus.

Worked example 2: a negative cubic term

Question. Complete the same table for y=−x3y=-x^3. Describe the sketch and its axis crossings. Non-calculator.

Plan. Negate each height in the previous table, keeping its input unchanged.

x=−2:y=−(−2)3=8negative of −8x=−1:y=−(−1)3=1negative of −1x=0:y=−03=0zero stays zerox=1,2:y=−1,−8negate the positive cubes\begin{aligned} x=-2:&\quad y=-(-2)^3=8 &&\text{negative of }-8\\ x=-1:&\quad y=-(-1)^3=1 &&\text{negative of }-1\\ x=0:&\quad y=-0^3=0 &&\text{zero stays zero}\\ x=1,2:&\quad y=-1,-8 &&\text{negate the positive cubes} \end{aligned}

Why this step? The minus is outside the power. It changes the output's sign after the input has been cubed.

Answer. Heights 8,1,0,−1,−88,1,0,-1,-8, in that order. The curve falls from top left to bottom right and crosses both axes at (0,0)(0,0).

Check. The point (2,−8)(2,-8) satisfies y=−(23)y=-(2^3).

[DIAGRAM: asset_name: Basic cubic shapes and a cubic with three crossings; asset_slug: aqa8300_a26_cubics; caption: Cubics can cross once or three times; the basic cubic flattens without turning at the origin; description: Three coordinate panels show y equals x cubed, y equals minus x cubed, and y equals x cubed minus x. The first two have their five table points marked. The third crosses the x-axis at minus 1, 0 and 1 and has two changes of direction. Each panel has labelled axes and a smooth curve.]
Cubics can cross once or three times

Not every cubic is the basic S. The third panel is y=x3−xy=x^3-x: at x=−1,0,1x=-1,0,1, its height is zero. Between those crossings it turns twice. Recognise the cubic term, then use the actual table or graph; do not give every cubic the same number of crossings or turns.

Watch out

Wrong: (−2)3=8(-2)^3=8, copied from the rule for squares. Right: (−2)3=−8(-2)^3=-8. An odd number of negative factors gives a negative product.

Try the negative cubic with a different coefficient. Its direction stays the same.

The reciprocal graph and its missing input

The rule y=1/xy=1/x asks for the reciprocal of the input. At x=2x=2, the height is 1/21/2; at x=100x=100, it is only 1/1001/100. The curve gets closer to the horizontal axis as the input grows, but the height never becomes zero.

Asymptote

A straight line that a branch of a curve approaches arbitrarily closely. For y=1/xy=1/x, both coordinate axes are asymptotes: the branches approach them but never meet them. This particular graph has no point at x=0x=0, because division by zero is undefined.

On the positive side, making xx smaller towards zero makes 1/x1/x very large. On the negative side, both coordinates are negative. These give two separate branches: one above and right of the origin, one below and left. Do not draw a line through the gap at zero.

The reciprocal graph

y=1xx≠0y=\frac1x\qquad x\ne0

Every point satisfies xy=1xy=1. There are no axis crossings. The axes x=0x=0 and y=0y=0 are asymptotes.

Not on the formulae sheet: learn it.

The points spread out unevenly: halving the input doubles the height. Choose a few small inputs as well as larger ones so the steep section is visible.

Worked example 3: the positive branch

Question. Work out the heights of y=1/xy=1/x at x=0.5,1,2,4x=0.5,1,2,4. Write down xx when y=0.4y=0.4. Non-calculator.

Plan. Divide 11 by each input, then use xy=1xy=1 for the requested height.

1÷0.5=2two halves fit into one1÷1=1reciprocal of one1÷2=0.5,1÷4=0.25halve and quarterx=1÷0.4=2.5use xy=1\begin{aligned} 1\div0.5&=2 &&\text{two halves fit into one}\\ 1\div1&=1 &&\text{reciprocal of one}\\ 1\div2&=0.5,\quad1\div4=0.25 &&\text{halve and quarter}\\ x&=1\div0.4=2.5 &&\text{use }xy=1 \end{aligned}

Why this step? The same product condition connects every pair of coordinates, including the point read backwards from its height.

Answer. Heights 2,1,0.5,0.252,1,0.5,0.25; when y=0.4y=0.4, x=2.5x=2.5. Sketch a smooth decreasing positive branch through these points, staying clear of both axes.

Check. 2.5×0.4=12.5\times0.4=1.

Now change only the signs of the inputs and the requested height. The negative branch follows the same reciprocal rule.

Continue this lesson.

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