FR3, FG13, HR3, HG15 - Scale drawings and bearings

FR3, FG13, HR3, HG15 - Scale drawings and bearings

Learn to turn map lengths into real distances, construct a consistent scale drawing, and describe directions using three-figure bearings. FR3 and HR3 supply the scale-factor reasoning; FG13 and HG15 combine accurate measurement with maps, angles and bearings.

Scale drawings

How can a route several kilometres long fit on a page without changing its shape? A scale drawing uses the same length multiplier everywhere, while keeping the angles unchanged.

Scale

A scale 1:n1:n means one unit on the drawing represents nn of the same unit in reality. At 1:25 0001:25\,000, 1 cm1\,\mathrm{cm} represents 25 000 cm=250 m25\,000\,\mathrm{cm}=250\,\mathrm m.

Convert units before using a ratio scale. Going from drawing to reality multiplies lengths by nn; going back divides by nn. A verbal scale such as “1 cm1\,\mathrm{cm} represents 10 m10\,\mathrm m” says the same thing in different units.

Worked example 1: drawing to reality

Question. A map has scale 1:25 0001:25\,000. A straight path measures 6.4 cm6.4\,\mathrm{cm} on it. Find the actual distance in kilometres.

Plan. Multiply by the scale factor in centimetres, then convert to kilometres.

Actual length=6.4×25 000=160 000 cm=1600 m=1.6 km\begin{aligned} \text{Actual length}&=6.4\times25\,000=160\,000\,\mathrm{cm}\\ &=1600\,\mathrm m=1.6\,\mathrm{km} \end{aligned}

Answer. 1.6 km1.6\,\mathrm{km}.

Check. Each map centimetre represents 0.25 km0.25\,\mathrm{km}, and 6.4×0.25=1.66.4\times0.25=1.6.

Reverse the question while keeping the scale and distance unchanged. This time division finds the length to draw.

Worked example 2: reality to drawing

Question. At scale 1:25 0001:25\,000, how long should a 1.6 km1.6\,\mathrm{km} straight path be drawn?

Plan. Convert the actual distance to centimetres, then divide by 25 00025\,000.

1.6 km=160 000 cmDrawing length=160 000÷25 000=6.4 cm\begin{aligned} 1.6\,\mathrm{km}&=160\,000\,\mathrm{cm}\\ \text{Drawing length}&=160\,000\div25\,000=6.4\,\mathrm{cm} \end{aligned}

Answer. Draw 6.4 cm6.4\,\mathrm{cm}.

Check. Reversing the conversion gives 6.4×25 000=160 000 cm6.4\times25\,000=160\,000\,\mathrm{cm}, the required distance.

For a construction on paper, calculate every drawing length first. For example, an 80 m80\,\mathrm m by 50 m50\,\mathrm m rectangular park at 1 cm:10 m1\,\mathrm{cm}:10\,\mathrm m becomes an 8 cm8\,\mathrm{cm} by 5 cm5\,\mathrm{cm} rectangle. Use a ruler from its zero mark, draw the given right angles, and join the vertices accurately. Do not use one scale horizontally and another vertically.

On a screen, resizing an image changes its physical centimetres. Use a labelled scale bar or supplied measurements rather than treating a centimetre on your screen as a printed map centimetre.

Watch out

1:25 0001:25\,000 does not mean 1 cm:25 000 m1\,\mathrm{cm}:25\,000\,\mathrm m. The ratio compares the same units; convert afterwards.

Find a fresh construction length.

Measuring directions

A bearing describes a direction from a specified starting point, measured clockwise from north at that point.

Three-figure bearing

A bearing is the clockwise angle from north, written with three digits. North is 000∘000^\circ, east 090∘090^\circ, south 180∘180^\circ and west 270∘270^\circ. For instance, 40∘40^\circ east of north has bearing 040∘040^\circ.

To measure a bearing on paper, draw or locate the north line through the starting point. Put the protractor's centre at that point and its zero along north. Read clockwise towards the destination, using the appropriate scale. For an angle greater than 180∘180^\circ, measure the remaining smaller angle carefully and subtract it from 360∘360^\circ. Do not begin at the destination or measure from an eastward horizontal line.

[DIAGRAM: asset_name: Bearings on either side of north; asset_slug: bearings-from-north; caption: The same small angle from north can give different clockwise bearings.; description: Two exact compass diagrams show rays 40 degrees east of north and 40 degrees west of north, labelled bearings 040 degrees and 320 degrees respectively. North, east, south and west are marked, and the clockwise bearing sweeps begin at north.]
The same small angle from north can give different clockwise bearings.

Worked example 3: east of north

Question. From AA, point BB is 40∘40^\circ east of north. Write the bearing of BB from AA.

Plan. Begin at north through AA and measure clockwise to ABAB.

The clockwise angle is already 40∘40^\circ. Write it with three digits.

Answer. 040∘040^\circ.

Check. The direction lies between north 000∘000^\circ and east 090∘090^\circ, as 040∘040^\circ does.

Move the direction to the other side of north, keeping the small angle 40∘40^\circ. A bearing still travels clockwise.

Worked example 4: west of north

Question. From AA, point BB is 40∘40^\circ west of north. Write the bearing of BB from AA.

Plan. Subtract the small anticlockwise angle from a complete turn.

Bearing=360∘−40∘=320∘\text{Bearing}=360^\circ-40^\circ=320^\circ

Answer. 320∘320^\circ.

Check. Northwest directions have bearings between 270∘270^\circ and 360∘360^\circ, so 320∘320^\circ is in the correct quadrant.

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