FG14–FG15, HG16–HG17 - Perimeter and polygon areas

FG14–FG15, HG16–HG17 - Perimeter and polygon areas

Measure the distance around a shape and the space it covers. FG14 and HG16 supply area methods for rectangles, triangles, parallelograms and trapezia; FG15 and HG17 extend these to perimeters and composite figures. You will choose useful lengths, explain the formulae and keep length units separate from area units.

Perimeters

A rectangle is 12 cm12\,\mathrm{cm} wide and 9 cm9\,\mathrm{cm} high. A 5 cm5\,\mathrm{cm} by 4 cm4\,\mathrm{cm} rectangle is cut from its top-right corner. Does removing that corner make the perimeter smaller?

Perimeter

The perimeter is the total length of a shape's boundary. Trace around the outside once and include every boundary edge. Perimeter is measured in length units, such as centimetres.

Opposite sides of a rectangle are equal. For rectilinear figures, horizontal lengths can be added or subtracted to find other horizontal lengths; do the same separately for vertical lengths. A line used to split the interior is not part of the outer boundary.

Worked example 1: a rectangle

Question. Find the perimeter of a rectangle of width 12 cm12\,\mathrm{cm} and height 9 cm9\,\mathrm{cm}.

Plan. Add two widths and two heights.

P=12+9+12+9=42 cmP=12+9+12+9=42\,\mathrm{cm}

Answer. 42 cm42\,\mathrm{cm}.

Check. Grouping equal sides gives 2(12+9)=2×21=42 cm2(12+9)=2\times21=42\,\mathrm{cm}.

Keep the outer dimensions, but remove the stated corner. The boundary now has six edges.

[DIAGRAM: asset_name: Perimeter of a corner-cut rectangle; asset_slug: corner-cut-rectangle; caption: Match horizontal lengths with horizontal lengths and vertical lengths with vertical lengths.; description: Exact L-shaped polygon from a 12 cm by 9 cm rectangle with a 5 cm wide, 4 cm deep top-right corner removed. Boundary labels show bottom 12 cm, left 9 cm, top 7 cm and lower right 5 cm; the two notch edges are 5 cm and 4 cm.]
Match horizontal lengths with horizontal lengths and vertical lengths with vertical lengths.

Worked example 2: a stepped boundary

Question. Find the perimeter after the 5 cm5\,\mathrm{cm} by 4 cm4\,\mathrm{cm} corner is removed.

Plan. Find the shortened outer edges, then walk around all six edges.

12−5=7 cmremaining top edge9−4=5 cmremaining right edgeP=12+5+5+4+7+9=42 cm\begin{aligned} 12-5&=7\,\mathrm{cm} &&\text{remaining top edge}\\ 9-4&=5\,\mathrm{cm} &&\text{remaining right edge}\\ P&=12+5+5+4+7+9\\ &=42\,\mathrm{cm} \end{aligned}

Answer. 42 cm42\,\mathrm{cm}, unchanged from the rectangle.

Check. Cutting removed 5+4=9 cm5+4=9\,\mathrm{cm} from the original outer edges, but introduced notch edges of the same lengths. The boundary length is unchanged.

This conclusion applies to this rectangular corner cut. A hole or a curved cut can change the boundary differently; trace the actual edges rather than assume that removing material always reduces perimeter.

Watch out

Adding only 12+9+7+512+9+7+5 misses the two notch edges. Every exposed boundary edge counts, including an edge that turns into an indentation.

Try a new corner cut.

Area formulae

Area counts how many unit squares cover a flat region, so it uses squared units. A 4 cm4\,\mathrm{cm} by 3 cm3\,\mathrm{cm} rectangle contains three rows of four unit squares: 4×3=12 cm24\times3=12\,\mathrm{cm}^2.

A perpendicular height is measured at right angles to the chosen base. It is the separation between parallel lines containing the base and the opposite edge or vertex. A sloping side is usually a different length.

[DIAGRAM: asset_name: Polygon bases and perpendicular heights; asset_slug: polygon-area-heights; caption: The height meets the base direction at a right angle; a sloping side is not the height.; description: Four exact labelled panels show rectangle length and width, triangle base and perpendicular height, parallelogram base and perpendicular separation, and trapezium parallel sides a and b with perpendicular height h. Right-angle markers distinguish heights from sloping edges.]
The height meets the base direction at a right angle

Cutting a triangle from one end of a parallelogram and moving it to the other makes a rectangle of the same base and height, so its area is bhbh. Two identical triangles can make a parallelogram, so one triangle has half that area. Two identical trapezia can make a parallelogram with base a+ba+b and height hh, giving half of (a+b)h(a+b)h for each trapezium.

Polygon areas

Arectangle=lwAtriangle=12bhAparallelogram=bhAtrapezium=12(a+b)h\begin{aligned} A_{\text{rectangle}}&=lw\\ A_{\text{triangle}}&=\tfrac12 bh\\ A_{\text{parallelogram}}&=bh\\ A_{\text{trapezium}}&=\tfrac12(a+b)h \end{aligned}

For the last three formulae, hh is perpendicular to the base. In a trapezium, a,ba,b are the parallel side lengths. Use one length unit throughout. The trapezium formula is supplied on the additional formulae sheet; the rectangle, triangle and parallelogram formulae are not listed there.

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