FR1, FR12, HR1, HR12 - Unit rates and compound measures

FR1, FR12, HR1, HR12 - Unit rates and compound measures

Compare prices and pay using amounts per unit, relate distance to time, and convert rates by changing both units correctly. FR1/HR1 cover standard and compound-unit conversions; FR12/HR12 cover interpreting and using those measures.

Unit prices and pay

Is the cheaper packet always better value? Its price alone does not tell us how much we receive.

Rate and unit rate

A rate compares quantities with different units. A unit rate gives the amount for one unit of the other quantity. “£2.402.40 per kilogram” means each kilogram costs £2.402.40; “£1212 per hour” means each paid hour earns £1212.

To compare like products fairly, convert their quantities to the same unit, then divide price by quantity. State the unit of the result. A lower price per kilogram is better value for the same product, although pack size and how much is needed can still affect the purchase.

Worked example 1: comparing different masses

Question. The same rice is sold as 750 g750\,\mathrm g for £1.801.80 or 1.2 kg1.2\,\mathrm{kg} for £3.123.12. Which has the lower unit price?

Plan. Convert both masses to kilograms, then compare pounds per kilogram.

750 g=0.75 kg,1.80÷0.75=2.40,3.12÷1.2=2.60.750\,\mathrm g=0.75\,\mathrm{kg},\qquad 1.80\div0.75=2.40,\qquad 3.12\div1.2=2.60.

Answer. The 750 g750\,\mathrm g pack is better value: £2.40/kg2.40/\mathrm{kg} compared with £2.60/kg2.60/\mathrm{kg}.

Check. 6 kg6\,\mathrm{kg} would be eight small packs costing £14.4014.40, or five large packs costing £15.6015.60, confirming the comparison.

The larger pack can be better value in a different comparison: do the calculation each time.

Worked example 2: comparing capacities

Question. The same detergent costs £2.702.70 for 750 ml750\,\mathrm{ml}, or £6.806.80 for 22 litres. Compare the unit prices.

Plan. Express both capacities in litres and divide cost by litres.

750 ml=0.75 l,2.70÷0.75=3.60,6.80÷2=3.40.750\,\mathrm{ml}=0.75\,\mathrm l,\qquad 2.70\div0.75=3.60,\qquad 6.80\div2=3.40.

Answer. The 22-litre pack is better value: £3.403.40 per litre rather than £3.603.60 per litre.

Check. At the smaller pack's rate, 22 litres would cost 2×3.60=2\times3.60= £7.207.20, more than £6.806.80.

For hourly pay, multiply the hourly rate by paid time in hours. Convert minutes by dividing by 6060, not by 100100.

Worked example 3: pay for part of an hour

Question. A worker earns £12.4012.40 per hour and works 33 hours 4545 minutes, all paid at that rate. Find the pay.

Plan. Convert 4545 minutes into a fraction of an hour.

3+4560=3.75 hours,12.40×3.75=46.50.3+\frac{45}{60}=3.75\text{ hours},\qquad 12.40\times3.75=46.50.

Answer. £46.5046.50.

Check. Three hours earns £37.2037.20; three quarters of an hour earns £9.309.30. Their sum is £46.5046.50.

When rates change, divide the paid time into the appropriate bands before multiplying.

Worked example 4: overtime and an unpaid break

Question. A shift runs from 08:0008{:}00 to 18:0018{:}00, including a 3030-minute unpaid break. The first 88 paid hours earn £1212 per hour; later time earns one and a half times that rate. Find total pay.

Plan. Remove unpaid time, then separate normal and overtime hours.

The shift lasts 1010 hours, so paid time is 9.59.5 hours. Overtime is 9.5−8=1.59.5-8=1.5 hours at 1.5×12=1.5\times12= £1818 per hour.

pay=8×12+1.5×18=96+27=123.\text{pay}=8\times12+1.5\times18=96+27=123.

Answer. £123123.

Check. Normal-rate pay for all 9.59.5 hours would be £114114. The overtime premium adds 1.5×6=1.5\times6= £99, giving £123123.

Read payment conditions literally. A charge for “each hour or part of an hour” uses a whole charged hour for any started hour; it is different from proportional payment for exact hours.

Watch out

33 hours 4545 minutes is 3.753.75 hours, not 3.453.45. “Per hour” tells you the unit needed before multiplying.

Use both unit-price and pay reasoning.

Speed

Speed measures distance travelled per unit time. A speed of 48 km/h48\,\mathrm{km/h} means 4848 kilometres per hour. Average speed uses the total distance and total elapsed time for the journey being described, including stops within that journey.

Distance, speed and time

average speed=total distancetotal time,distance=speed×time,time=distancespeed.\text{average speed}=\frac{\text{total distance}}{\text{total time}},\qquad \text{distance}=\text{speed}\times\text{time},\qquad \text{time}=\frac{\text{distance}}{\text{speed}}.

Use consistent units: kilometres with hours gives kilometres per hour. These relationships are methods to know, not supplied formulas on the formula sheet.

Average speed need not equal the speed at each instant. Multiplying average speed by the corresponding elapsed time still gives the total distance.

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