4.5, 4.11 - Maps and scale drawings

4.5, 4.11 - Maps and scale drawings

A map or plan shrinks real lengths by one consistent scale. Use construction skills from 4.5 to make accurate plans, and the map skills in 4.11 to convert distances and compare routes. You will work with ratio scales, scale bars and labelled lengths.

Scale and common units

A map route measures 6.4 cm6.4\,\mathrm{cm} at scale 1:25 0001:25\,000. Is that a short walk or a long journey? The scale turns a paper measurement into a real distance, but the units must agree first.

You already know

A ratio compares quantities in the same unit. Use 1 m=100 cm1\,\mathrm{m}=100\,\mathrm{cm} and 1 km=1000 m=100 000 cm1\,\mathrm{km}=1000\,\mathrm{m}=100\,000\,\mathrm{cm}. Measure paper lengths carefully with a ruler.

At this scale, one centimetre represents 25 000 cm=250 m25\,000\,\mathrm{cm}=250\,\mathrm{m}. A map centimetre does not represent 25 00025\,000 metres.

Ratio scale

A scale 1:n1:n means one unit on the drawing represents nn of the same unit in reality. The ratio compares lengths. For example, 1:1001:100 means 1 cm1\,\mathrm{cm} represents 100 cm100\,\mathrm{cm}.

Multiplication enlarges a drawing length to its real length. Division shrinks a real length to fit the drawing. The unit stays the same during that multiplication or division; convert afterwards if helpful.

Scale conversion

For lengths in the same unit,

real length=n×drawing length,drawing length=real lengthn\text{real length}=n\times\text{drawing length},\qquad \text{drawing length}=\frac{\text{real length}}{n}

These are linear lengths, not areas. Not in the formulae sheet at either tier: learn it.

Start with the opening map measurement and keep track of the unit at each line.

Worked example 1: map to reality

Question. Find the real distance in kilometres represented by 6.4 cm6.4\,\mathrm{cm} at 1:25 0001:25\,000.

Plan. Multiply to find real centimetres, then convert to kilometres.

L=6.4×25 000=160 000 cmapply the scaleL=1600 m=1.6 kmconvert units\begin{aligned} L&=6.4\times25\,000=160\,000\,\mathrm{cm} &&\text{apply the scale}\\ L&=1600\,\mathrm{m}=1.6\,\mathrm{km} &&\text{convert units} \end{aligned}

Why multiply? The real route is 25 00025\,000 times the drawing length.

Answer. 1.6 km1.6\,\mathrm{km}.

Check. Each map centimetre means 250 m250\,\mathrm{m}, and 6.4×250=16006.4\times250=1600.

Change only the map measurement. The conversion per centimetre stays fixed.

Worked example 2: a longer map distance

Question. Find the real distance in kilometres represented by 8.4 cm8.4\,\mathrm{cm} at 1:25 0001:25\,000.

Plan. Use the same scale and unit conversion.

L=8.4×25 000=210 000 cmmap to realityL=210 000100 000=2.1 kmcentimetres to kilometres\begin{aligned} L&=8.4\times25\,000=210\,000\,\mathrm{cm} &&\text{map to reality}\\ L&=\frac{210\,000}{100\,000}=2.1\,\mathrm{km} &&\text{centimetres to kilometres} \end{aligned}

Why divide by 100 000100\,000 last? There are that many centimetres in one kilometre.

Answer. 2.1 km2.1\,\mathrm{km}.

Check. The extra 2 cm2\,\mathrm{cm} represents 500 m500\,\mathrm{m}; 1.6+0.5=2.11.6+0.5=2.1.

For planning, the real distance may be known instead. Convert it to centimetres before dividing by the scale denominator.

Worked example 3: reality to map

Question. How many centimetres represent 2 km2\,\mathrm{km} at 1:25 0001:25\,000?

Plan. Express the real distance in centimetres, then shrink it.

2 km=200 000 cmuse common unitsl=200 00025 000=8 cmdivide by the scale\begin{aligned} 2\,\mathrm{km}&=200\,000\,\mathrm{cm} &&\text{use common units}\\ l&=\frac{200\,000}{25\,000}=8\,\mathrm{cm} &&\text{divide by the scale} \end{aligned}

Why divide? We need the small drawing length rather than its much larger real counterpart.

Answer. 8 cm8\,\mathrm{cm}.

Check. 8×250=2000 m=2 km8\times250=2000\,\mathrm{m}=2\,\mathrm{km}.

Change only the real distance. Use the same denominator and the same unit conversion.

Worked example 4: a different real distance

Question. How many centimetres represent 3 km3\,\mathrm{km} at 1:25 0001:25\,000?

Plan. Convert, then divide.

3 km=300 000 cmconvert firstl=300 00025 000=12 cmapply the ratio\begin{aligned} 3\,\mathrm{km}&=300\,000\,\mathrm{cm} &&\text{convert first}\\ l&=\frac{300\,000}{25\,000}=12\,\mathrm{cm} &&\text{apply the ratio} \end{aligned}

Why use centimetres? The requested map length is in centimetres, so the real length must use the same unit before division.

Answer. 12 cm12\,\mathrm{cm}.

Check. 12×250=3000 m12\times250=3000\,\mathrm{m}.

A smaller denominator gives a larger drawing of the same object: 1:1001:100 shows it larger than 1:10001:1000. Use this direction check when choosing whether to multiply or divide.

Watch out

Wrong: 2÷25 0002\div25\,000 gives the map length in centimetres for 2 km2\,\mathrm{km}. The units do not match. Correct: 200 000÷25 000=8 cm200\,000\div25\,000=8\,\mathrm{cm}.

Keep the scale fixed and change the real distance again.

Routes and scale bars

A route follows its actual path; a straight line joins only the endpoints. Those lengths can differ even when both measurements are accurate.

Scale bar

A drawn segment labelled with the real distance it represents. Compare a map length with the bar using the same ruler or the same grid intervals.

A scale bar has a useful advantage: if a map and its bar are enlarged together, they still give the correct real distance. Both measured lengths multiply by the same factor, so their ratio is unchanged. For example, 7÷2=14÷47\div2=14\div4. A printed ratio such as 1:25 0001:25\,000 assumes the intended printing size; doubling that size changes the physical scale to 1:12 5001:12\,500.

[DIAGRAM: asset_slug: m064_map_routes; caption: The route A–B–C is seven intervals and the shortcut A–C is five; description: AB is four grid intervals and BC is three; the scale bar spans two intervals and represents 500 m; screen centimetres are not a physical map scale; file: map_routes.png; recommended_method: matplotlib]
The route A–B–C is seven intervals and the shortcut A–C is five

Count the labelled intervals here. Do not put a ruler against the screen and treat screen centimetres as map centimetres.

Worked example 5: route and shortcut

Question. On the map, ABAB is four intervals, BCBC is three and the supplied straight distance ACAC is five. Each interval represents 250 m250\,\mathrm{m}. How much distance does the shortcut save?

Plan. Add the route pieces, convert both paths and subtract.

AB+BC=4+3=7 intervalsfollow the routeLroute=7×250=1750 mconvert all piecesLstraight=5×250=1250 muse the supplied distancesaving=1750−1250=500 mcompare paths\begin{aligned} AB+BC&=4+3=7\text{ intervals} &&\text{follow the route}\\ L_{\mathrm{route}}&=7\times250=1750\,\mathrm{m} &&\text{convert all pieces}\\ L_{\mathrm{straight}}&=5\times250=1250\,\mathrm{m} &&\text{use the supplied distance}\\ \text{saving}&=1750-1250=500\,\mathrm{m} &&\text{compare paths} \end{aligned}

Why add before converting? Every route piece uses the same scale, so their sum can be scaled in one step.

Answer. The shortcut saves 500 m500\,\mathrm{m}.

Check. It removes two intervals: 2×250=500 m2\times250=500\,\mathrm{m}.

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