4.4 - Measuring, estimating and bearings

4.4 - Measuring, estimating and bearings

You will read scales, calculate elapsed times and choose sensible estimates. You will also measure angles to the nearest degree and describe directions using three-figure bearings. Each skill starts by choosing the correct unit, starting point or zero.

Reading measuring instruments

A night bus leaves at 22:4522{:}45 and arrives at 01:2001{:}20 the next day. How long is the journey? Reading a clock, like reading a ruler, means understanding its scale rather than just subtracting the printed digits. We will return to the bus shortly.

You already know

You can subtract two readings and divide a total into equal parts. 1 m=100 cm1\,\mathrm{m}=100\,\mathrm{cm}, 1 kg=1000 g1\,\mathrm{kg}=1000\,\mathrm{g}, and 1 h=60 min1\,\mathrm{h}=60\,\mathrm{min}.

On a measuring scale, labels tell you the value of equal gaps. Count intervals, not tick marks: six ticks enclose five gaps.

Reading an equally spaced scale

value of one interval=difference between labelled valuesnumber of intervalsreading=starting label+interval count×interval value\begin{aligned} \text{value of one interval}&=\frac{\text{difference between labelled values}}{\text{number of intervals}}\\ \text{reading}&=\text{starting label}+\text{interval count}\times\text{interval value} \end{aligned}

Follow the increasing direction on the scale. For Foundation and Higher: Not in the formulae sheet: learn it.

A ruler's physical edge may not be its zero mark. Place the starting endpoint at zero, or subtract the readings at both endpoints. For a thermometer or balance, follow the increasing labels even when some are negative. For a liquid measure, keep the vessel upright and read at eye level; when instructed, read the bottom of the curved surface, or meniscus. Looking from above or below can shift the apparent reading: this is parallax.

[DIAGRAM: asset_slug: instrument_scales; caption: Ruler, thermometer and jug scales with pointers; description: Ruler labelled in centimetres with object endpoints 1.2 and 4.7. Thermometer has one-degree gaps and pointer 6 degrees C. Jug has five equal gaps between 200 and 400 mL with pointer at the fourth above 200. Use labels, not physical screen dimensions; file: instrument_scales.png; recommended_method: matplotlib]
Ruler, thermometer and jug scales with pointers

The ruler gives length 4.7−1.2=3.5 cm4.7-1.2=3.5\,\mathrm{cm}. The thermometer's gap is (5−0)÷5=1∘C(5-0)\div5=1^\circ\mathrm{C}, so its pointer reads 6∘C6^\circ\mathrm{C}. These are labelled scales: enlarging the picture does not change the readings. Do not measure screen centimetres with a physical ruler.

Worked example 1: read the jug scale

Question. A jug has five equal intervals between 200 mL200\,\mathrm{mL} and 400 mL400\,\mathrm{mL}. The pointer is four intervals above 200 mL200\,\mathrm{mL}. Find the volume.

Plan. Find one interval, then count upwards from the lower label.

interval=(400−200)÷5=40 mLshare the labelled differencevolume=200+4×40four intervals above 200=360 mLadd\begin{aligned} \text{interval}&=(400-200)\div5=40\,\mathrm{mL} &&\text{share the labelled difference}\\ \text{volume}&=200+4\times40 &&\text{four intervals above }200\\ &=360\,\mathrm{mL} &&\text{add} \end{aligned}

Why start at 200200? The pointer's interval count starts there, not at zero.

Answer. 360 mL360\,\mathrm{mL}.

Check. One further interval gives 360+40=400 mL360+40=400\,\mathrm{mL}, the upper label.

Change only the pointer position, from four intervals to three above the same lower label.

[DIAGRAM: asset_slug: jug_variations; caption: Jug scales with changed pointer positions and labels; description: First panel repeats the 200 to 400 mL scale with pointer four intervals above 200. Second uses the same scale with pointer three intervals above 200. Third has five intervals from 100 to 250 mL and pointer two intervals above 100; file: jug_variations.png; recommended_method: matplotlib]
Jug scales with changed pointer positions and labels

The spacing value stays fixed in the middle panel.

Worked example 2: move the pointer

Question. The same scale has a pointer three intervals above 200 mL200\,\mathrm{mL}. Find the volume.

Plan. Keep the interval value and change only the number of intervals counted.

interval=(400−200)÷5=40 mLunchanged labelsvolume=200+3×40three intervals=320 mLadd\begin{aligned} \text{interval}&=(400-200)\div5=40\,\mathrm{mL} &&\text{unchanged labels}\\ \text{volume}&=200+3\times40 &&\text{three intervals}\\ &=320\,\mathrm{mL} &&\text{add} \end{aligned}

Why keep 40 mL40\,\mathrm{mL}? Moving a pointer does not change the scale's labels or spacing.

Answer. 320 mL320\,\mathrm{mL}.

Check. Two further intervals give 320+2×40=400 mL320+2\times40=400\,\mathrm{mL}.

If the labels change instead, recalculate the interval value before counting. The unit is part of the reading.

Watch out

The line interval=(400−200)÷6\text{interval}=(400-200)\div6 counts six ticks instead of five gaps. The correct calculation is 200÷5=40 mL200\div5=40\,\mathrm{mL}.

Use the final panel, with its new labels, for this check.

Time intervals and clock notation

A clock uses groups of sixty minutes, not hundredths of an hour. For the bus, count forwards through midnight instead of subtracting the smaller arrival hour from the departure hour.

Clock notation

The 12-hour clock uses am and pm. The 24-hour clock runs from 00:0000{:}00 to 23:5923{:}59. Midnight is 00:0000{:}00, or 12:0012{:}00 am; noon is 12:0012{:}00, or 12:0012{:}00 pm.

For afternoon and evening times other than 1212 pm, add twelve to the hour: 3:203{:}20 pm becomes 15:2015{:}20. At 1212 am use hour zero. Minutes do not change. These clock conventions and the 6060-minute conversion are absent from both tier formulae sheets: learn them.

Worked example 3: the night bus

Question. A bus leaves at 22:4522{:}45 and arrives at 01:2001{:}20 the next day. Find the journey time in hours and minutes.

Plan. Count to midnight, then from midnight to arrival.

22:45 to 24:00=1 h 15 minreach midnight00:00 to 01:20=1 h 20 minnext daytotal=2 h 35 minadd the intervals\begin{aligned} 22{:}45\text{ to }24{:}00&=1\,\mathrm{h}\ 15\,\mathrm{min} &&\text{reach midnight}\\ 00{:}00\text{ to }01{:}20&=1\,\mathrm{h}\ 20\,\mathrm{min} &&\text{next day}\\ \text{total}&=2\,\mathrm{h}\ 35\,\mathrm{min} &&\text{add the intervals} \end{aligned}

Why split at midnight? The clock restarts at zero, but elapsed time keeps increasing.

Answer. 22 hours 3535 minutes.

Check. 75+80=15575+80=155 minutes, and 155=2×60+35155=2\times60+35. The endpoints are 10:4510{:}45 pm and 1:201{:}20 am.

Change only the arrival time to 01:5001{:}50 the next day.

Worked example 4: a later arrival

Question. A bus leaves at 22:4522{:}45 and arrives at 01:5001{:}50 the next day. Find its journey time.

Plan. Keep the first interval to midnight, then use the new arrival time.

to midnight=75 minunchanged departureafter midnight=110 min1×60+50total=75+110=185 minadd=3 h 5 min185=3×60+5\begin{aligned} \text{to midnight}&=75\,\mathrm{min} &&\text{unchanged departure}\\ \text{after midnight}&=110\,\mathrm{min} &&1\times60+50\\ \text{total}&=75+110=185\,\mathrm{min} &&\text{add}\\ &=3\,\mathrm{h}\ 5\,\mathrm{min} &&185=3\times60+5 \end{aligned}

Why carry sixty minutes? An hour contains sixty minutes, so 22 hours 6565 minutes becomes 33 hours 55 minutes.

Answer. 33 hours 55 minutes.

Check. Arrival is 3030 minutes later than in Example 3; the duration also increases by 3030 minutes.

The same forward-counting method works during a day. From 1:351{:}35 pm to 4:104{:}10 pm is 2525 minutes to 2:002{:}00 pm, then 22 hours 1010 minutes: 22 hours 3535 minutes altogether. For a journey lasting several days, include every complete day named in the question.

Watch out

The line 2 h 35 min=2.35 h2\,\mathrm{h}\ 35\,\mathrm{min}=2.35\,\mathrm{h} is wrong. The correct decimal conversion is 2+35/602+35/60 hours, because minutes are sixtieths of an hour.

Read “next day” carefully before doing the next subtraction.

Choosing sensible estimates

An estimate needs the right scale before it needs extra decimal places. Think about the object, choose a familiar comparison, then check the unit.

Estimate

An estimate is an approximate value chosen for a purpose. It is supported by a sensible reference or calculation; it is not an unexplained guess.

A long stride gives a rough metre reference, a large drink carton a rough litre reference, and a minute contains sixty seconds. Objects vary: these comparisons are aids, not definitions or exact measurements of every object.

MeasureA useful comparison
LengthA room may be a few metres; a road journey many kilometres
MassA small food item may weigh tens or hundreds of grams; an adult's mass is better expressed in kilograms
CapacityA drink container may hold hundreds of millilitres, rather than hundreds of litres
TimeCrossing a classroom takes seconds; a lesson takes tens of minutes
AngleCompare a turn with a quarter turn or a half turn

There is no formula-sheet entry for choosing an estimate on either tier. The justification comes from the scale and your comparison.

Worked example 5: estimate a doorway height

Question. Which is a sensible height for an ordinary classroom doorway: 0.2 m0.2\,\mathrm{m}, 2 m2\,\mathrm{m} or 200 m200\,\mathrm{m}? Explain.

Plan. Compare each choice with the height needed for people to walk through.

0.2 m=20 cmfar too low2 m=200 cmperson-height scale200 m=20 000 cmtall-building scale\begin{aligned} 0.2\,\mathrm{m}&=20\,\mathrm{cm} &&\text{far too low}\\ 2\,\mathrm{m}&=200\,\mathrm{cm} &&\text{person-height scale}\\ 200\,\mathrm{m}&=20\,000\,\mathrm{cm} &&\text{tall-building scale} \end{aligned}

Why use a person as the reference? A doorway is designed for people to pass through upright.

Answer. About 2 m2\,\mathrm{m} is sensible.

Check. It is taller than many people but remains a room-sized length. It is an estimate, not the measured height of every doorway.

Keep the object and physical choices the same. Change only the unit from metres to centimetres.

Worked example 6: the same estimate in another unit

Question. Which doorway height is sensible: 20 cm20\,\mathrm{cm}, 200 cm200\,\mathrm{cm} or 20 000 cm20\,000\,\mathrm{cm}? Explain.

Plan. Convert to familiar metre lengths before comparing.

20 cm=20÷100=0.2 mcentimetres to metres200 cm=200÷100=2 mcentimetres to metres20 000 cm=20 000÷100=200 mcentimetres to metres\begin{aligned} 20\,\mathrm{cm}&=20\div100=0.2\,\mathrm{m} &&\text{centimetres to metres}\\ 200\,\mathrm{cm}&=200\div100=2\,\mathrm{m} &&\text{centimetres to metres}\\ 20\,000\,\mathrm{cm}&=20\,000\div100=200\,\mathrm{m} &&\text{centimetres to metres} \end{aligned}

Why convert first? A larger printed number may describe exactly the same physical height in a smaller unit.

Answer. 200 cm200\,\mathrm{cm}, because it is 2 m2\,\mathrm{m}, a sensible doorway height.

Check. The selected physical height agrees with Example 5.

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