Physics 12.13 - Force on a current-carrying conductor
Calculate the force on a perpendicular current-carrying conductor, convert centimetres and millinewtons, and rearrange the equation to find field strength, current or the length within the field. This is Higher-tier content.
Force, field, current and length
Fleming’s left-hand rule predicts force direction. To calculate the magnitude for a straight conductor at right angles to a uniform magnetic field, use:
Force on a perpendicular conductor
| Symbol | Quantity | SI unit |
|---|---|---|
| Force on the conductor | newton, | |
| Magnetic flux density: a measure of field strength | tesla, , equivalent to | |
| Conventional current | ampere, | |
| Length of conductor inside the field | metre, |
The symbol is a lower-case L, not the number 1. A wire may be long, but only its section within the magnetic field contributes to this calculation. The equation above applies when the wire and field are perpendicular; do not use it as the full force for any angle.
For fixed field and length, doubling current doubles force. Similarly, doubling either or alone doubles force. Reversing current changes force direction, but keeping its magnitude unchanged keeps the same force magnitude.
Converting units and calculating force
Worked example: finding force
A wire section is perpendicular to a field of flux density . It carries . Calculate the force.
Convert the length before substituting:
To two significant figures, the force is . Using 6.0 as the length in metres would give a force 100 times too large. A small force is reasonable for this short wire.
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