6D.30-6D.32 - Halogenoalkane Reactions

6D.30-6D.32 - Halogenoalkane Reactions

Replacing a halogen can make an alcohol, a nitrile or an amine; removing it together with a neighbouring hydrogen makes an alkene. Learn to classify the starting molecule and choose the reagent, solvent and attacking species for each route.

Classifying The Carbon Attached To X

A halogenoalkane contains a carbon-halogen bond, written generally as R−X\ce{R-X}, where X\ce{X} is usually Cl\ce{Cl}, Br\ce{Br} or I\ce{I}. The classification does not depend on the whole molecule; it depends on the carbon atom directly bonded to the halogen.

ClassificationCarbon bonded to halogen is also bonded toExampleReason
Primaryone other carbon atomCHX3CHX2CHX2Br\ce{CH3CH2CH2Br}the C−Br\ce{C-Br} carbon is at the end of the chain
Secondarytwo other carbon atomsCHX3CHBrCHX3\ce{CH3CHBrCH3}the C−Br\ce{C-Br} carbon is in the middle of the chain
Tertiarythree other carbon atoms(CHX3)X3CBr\ce{(CH3)3CBr}the C−Br\ce{C-Br} carbon is attached to three carbon groups

The common error is to classify by the halogen itself or by the longest chain. Instead, circle the carbon attached to X\ce{X}, then count how many carbon atoms are directly bonded to that carbon.

Worked classification:

CHX3CHX2CHBrCHX3\ce{CH3CH2CHBrCH3} is a secondary halogenoalkane. The carbon bearing Br\ce{Br} is bonded to the CHX3\ce{CH3} group on one side and the CHX3CHX2\ce{CH3CH2} group on the other side, so it is bonded directly to two carbon atoms.

[DIAGRAM: asset_name: Halogenoalkane Carbon Classes; asset_slug: organic_halogen_classes; recommended_method: deterministic_chart; description: Primary, secondary and tertiary bromoalkanes: count the carbon groups directly attached to the carbon bearing bromine.]
Diagram

Nucleophiles And The Polar C-X Bond

The carbon–halogen bond creates an electron-deficient carbon that can accept a lone pair from a reagent.

Nucleophile

An electron-pair donor.

A nucleophile is attracted to an electron-deficient atom and uses an available electron pair, usually a lone pair, to form a new covalent bond.

Halogenoalkanes are vulnerable to nucleophiles because the halogen is more electronegative than carbon. The C−X\ce{C-X} bond is polar: the carbon is δ+\delta^{+} and the halogen is δ−\delta^{-}. That makes the carbon atom attached to the halogen an electrophilic site, so electron-rich species can attack it.

Useful nucleophiles in this lesson:

SpeciesWhy it can act as a nucleophileReaction in this lesson
OHX−\ce{OH-}negative ion with lone pairs on oxygensubstitution with aqueous KOH\ce{KOH}
HX2O\ce{H2O}lone pairs on oxygen, even though the molecule is neutralreaction with aqueous silver nitrate in ethanol
CNX−\ce{CN-}negative ion with a lone pair; carbon end forms the new C−C\ce{C-C} bondsubstitution with potassium cyanide
NHX3\ce{NH3}lone pair on nitrogensubstitution to make a primary amine

Nucleophile is a role, not a permanent label. OHX−\ce{OH-} acts as a nucleophile in aqueous potassium hydroxide, but as a base in ethanolic potassium hydroxide. The condition changes the main reaction pathway.

Neutral molecules can be nucleophiles

Ammonia can be a nucleophile even though it has no negative charge: the nitrogen atom in NHX3\ce{NH3} has a lone pair that can be donated to an electron-deficient carbon; negative charge often helps, but it is not required for nucleophilic behaviour.

Substitution To Alcohols

Warm or heat the halogenoalkane with aqueous potassium hydroxide to form an alcohol; reflux allows longer heating without losing volatile reactants. The hydroxide ion acts as a nucleophile and replaces the halide ion.

General ionic equation:

R−X+OHX−→R−OH+XX−\ce{R-X + OH- -> R-OH + X-}

Example with bromoethane:

CHX3CHX2Br+KOH(aq)→CHX3CHX2OH+KBr\ce{CH3CH2Br + KOH(aq) -> CH3CH2OH + KBr}

The condition aqueous matters. In water, hydroxide ions are well placed to donate a lone pair to the δ+\delta^{+} carbon and substitute the halogen. In explanations, do not just name the reagent; state the role of OHX−\ce{OH-} and the product functional group.

Common-error contrast:

PromptStrong answerTempting but weak answer
What forms when 1-bromopropane is heated with aqueous KOH\ce{KOH}?propan-1-ol, by substitution of Br\ce{Br} by OH\ce{OH}"an alkene", which would need ethanolic KOH\ce{KOH} as the main condition
What is the role of OHX−\ce{OH-} here?nucleophile / electron-pair donor"catalyst", because OHX−\ce{OH-} is consumed in the substitution equation

Water As Nucleophile With Silver Nitrate

Aqueous silver nitrate in ethanol gives another hydrolysis route. In this reaction mixture, water acts as the nucleophile and substitutes the halogen to form an alcohol. The released halide ion then reacts with silver ions to form a silver halide precipitate.

The organic change can be represented as:

R−X+HX2O→R−OH+HX++XX−\ce{R-X + H2O -> R-OH + H+ + X-}

The observation-forming step is:

AgX++XX−→AgX(s)\ce{Ag+ + X- -> AgX(s)}

For bromoethane:

CHX3CHX2Br+HX2O→CHX3CHX2OH+HX++BrX−\ce{CH3CH2Br + H2O -> CH3CH2OH + H+ + Br-} AgX++BrX−→AgBr(s)\ce{Ag+ + Br- -> AgBr(s)}

Ethanol helps the organic halogenoalkane mix with the aqueous reagent. Silver ions remove halide ions as a precipitate, so the appearance of AgX(s)\ce{AgX(s)} is evidence that XX−\ce{X-} has been released.

The silver halide is white for chloride, cream for bromide and yellow for iodide. This observation follows release of the halide; silver nitrate does not replace the halogen in the organic molecule.

New Functional Groups From Cyanide And Ammonia

Potassium cyanide and ammonia both substitute the halogen, but the synthetic consequence is different.

Continue this lesson.

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