2A.1-2A.6 - Ionic Bonding

2A.1-2A.6 - Ionic Bonding

Use ionic charge, radius and electron arrangements to explain the strength of a giant ionic lattice. Draw the ions formed by electron transfer, then use conductivity and directed migration as evidence for mobile charged particles.

Ionic Bonding Is A Force, Not A Tiny Stick

A crystal of sodium chloride looks quiet, but the particle model is full of strong attractions. The solid is not made from separate NaCl\ce{NaCl} molecules. It is a giant ionic lattice: a repeating arrangement of positive and negative ions, with each ion attracted to oppositely charged ions around it.

Ionic bond

The strong electrostatic attraction between oppositely charged ions.

The word electrostatic matters because the attraction is between charges, not between electron pairs shared in a local bond. In an ionic lattice the attraction acts in all directions through the structure.

The strength of ionic bonding depends mainly on two linked ideas.

FactorEffect on attractionWhy it matters
Ionic chargeHigher positive and negative charges give stronger attractionMgX2+\ce{Mg^2+} and OX2−\ce{O^2-} attract more strongly than NaX+\ce{Na+} and ClX−\ce{Cl-}
Ionic radiusSmaller ions can get closer together, giving stronger attractionNaX+\ce{Na+} attracts a given anion more strongly than the larger KX+\ce{K+} does

Charge and radius decide ionic strength

Larger ionic charges and smaller ionic radii give stronger electrostatic attractions between oppositely charged ions.

Do not turn this into a full lattice-energy calculation here. The specification later treats lattice energy quantitatively; in this lesson the charge/radius model explains trends and evidence.

Worked example: choosing the stronger ionic bonding

Suppose two ionic compounds have the same lattice type: NaF\ce{NaF} and KF\ce{KF}.

  1. The anion is the same in both compounds: FX−\ce{F-}.
  2. The cation charge is the same: NaX+\ce{Na+} and KX+\ce{K+} are both +1+1.
  3. The deciding factor is radius. NaX+\ce{Na+} is smaller than KX+\ce{K+}.
  4. The smaller NaX+\ce{Na+} can approach FX−\ce{F-} more closely, so the electrostatic attraction is stronger in NaF\ce{NaF}.

The key explanation is not just "sodium is smaller". It is: the smaller NaX+\ce{Na+} ion gives a shorter distance between oppositely charged ions, so the electrostatic attraction is stronger.

Forming Ions By Electron Transfer

Atoms form simple ions by losing or gaining electrons. Losing electrons gives a positive ion, called a cation, because there are now more protons than electrons. Gaining electrons gives a negative ion, called an anion, because there are now more electrons than protons.

The charge tells you the electron transfer.

ParticleElectron changeIon formedElectron configuration change
sodium atomloses 1 electronNaX+\ce{Na+}2,8,1 → 2,8
magnesium atomloses 2 electronsMgX2+\ce{Mg^2+}2,8,2 → 2,8
chlorine atomgains 1 electronClX−\ce{Cl-}2,8,7 → 2,8,8
oxygen atomgains 2 electronsOX2−\ce{O^2-}2,6 → 2,8

In dot-and-cross diagrams for ionic compounds, dots and crosses show where the outer-shell electrons came from. They do not show a shared electron pair. A good ionic dot-and-cross diagram has three visible features:

  1. Each ion is shown separately, usually in square brackets.
  2. The charge is written outside the bracket, such as [Na]X+\ce{[Na]+} or [O]X2−\ce{[O]^2-}.
  3. The anion has a full outer shell, with transferred electron(s) shown using the other symbol.

Worked example: drawing sodium chloride

Sodium has one outer electron and chlorine has seven outer electrons. Sodium loses its outer electron to form NaX+\ce{Na+}. Chlorine gains that electron to form ClX−\ce{Cl-}, so the chloride ion has eight outer-shell electrons.

A written planning route is:

Na: 2,8,1 → NaX+\ce{Na+}: 2,8 + eX−\ce{e-}

Cl: 2,8,7 + eX−\ce{e-} → ClX−\ce{Cl-}: 2,8,8

Overall ions: [Na]X+\ce{[Na]+} and [Cl]X−\ce{[Cl]-}

Dot-and-cross: chloride has seven of chlorine's own outer electrons plus one transferred electron from sodium.

Worked example: drawing magnesium oxide

Magnesium loses two electrons to form MgX2+\ce{Mg^2+}. Oxygen gains two electrons to form OX2−\ce{O^2-}. The oxide ion should have eight outer-shell electrons: six originally from oxygen and two transferred from magnesium.

Mg: 2,8,2 → MgX2+\ce{Mg^2+}: 2,8 + 2eX−2\ce{e-}

O: 2,6 + 2eX−2\ce{e-} → OX2−\ce{O^2-}: 2,8

Overall ions: [Mg]X2+\ce{[Mg]^2+} and [O]X2−\ce{[O]^2-}

Dot-and-cross: oxide has six of oxygen's own outer electrons plus two transferred electrons from magnesium.

A common error is to draw a line between the ions, as if the transferred electron has become a covalent bond. Here, the diagram must communicate electron loss/gain and charged ions, not shared pairs.

[DIAGRAM: asset_name: Ionic Dot And Cross; asset_slug: edexcel_a_level_chemistry_l008_ionic_dot_cross; recommended_method: matplotlib; description: Outer-shell diagrams of sodium chloride and magnesium oxide with separate bracketed ions, whole-ion charges and electron origins.]
Diagram

Charge Density And Stronger Ionic Attraction

The charge/radius model becomes more powerful when you treat ions as charged spheres.

Charge density

The charge of an ion relative to its size: a small ion with a high charge has a high charge density.

High charge density means the electric field around the ion is strong, so it attracts oppositely charged ions strongly.

For early A-level bonding questions, you usually do not need a numerical value for charge density. You need to use it as a reasoning bridge:

higher charge and/or smaller radius

→ greater charge density

→ stronger electrostatic attraction between oppositely charged ions

→ stronger ionic bonding

This chain explains why compounds with 2+2+ and 2−2- ions often have higher melting temperatures than compounds with 1+1+ and 1−1- ions, provided the comparison is otherwise fair. More energy is needed to overcome stronger attractions in the lattice.

Worked example: explaining a melting-temperature difference

MgO\ce{MgO} has a much higher melting temperature than NaCl\ce{NaCl}.

The answer should not stop at "magnesium oxide is ionic". Both are ionic. The difference is that MgO\ce{MgO} contains MgX2+\ce{Mg^2+} and OX2−\ce{O^2-}, whereas NaCl\ce{NaCl} contains NaX+\ce{Na+} and ClX−\ce{Cl-}. The larger charges in MgO\ce{MgO} produce stronger electrostatic attractions between oppositely charged ions, so more energy is needed to overcome the attractions in the lattice.

If radius is also relevant, add it explicitly. For example, CaO\ce{CaO} would have weaker attraction than MgO\ce{MgO} if the anion and charges are kept the same, because CaX2+\ce{Ca^2+} is larger than MgX2+\ce{Mg^2+}.

Ionic Radius Trends

Ionic radius is not just "atomic radius with a charge label". It depends on the number of occupied electron shells, the number of protons in the nucleus, and the number of electrons being attracted.

Down a group, ionic radius increases. For example, LiX+\ce{Li+}, NaX+\ce{Na+}, and KX+\ce{K+} all have a +1+1 charge, but each step down the group adds an occupied electron shell. The outer electron shell is farther from the nucleus and there is more shielding, so the ion is larger.

Across an isoelectronic series, the trend is different.

Isoelectronic

Describes ions (or atoms) that have the same number of electrons and the same electron arrangement.

The classic example is:

NX3−\ce{N^3-}, OX2−\ce{O^2-}, FX−\ce{F-}, NaX+\ce{Na+}, MgX2+\ce{Mg^2+}, AlX3+\ce{Al^3+}

All six ions have 10 electrons, with the arrangement 2,8. The number of protons increases from nitrogen to aluminium:

IonNumber of protonsNumber of electronsRelative radius idea
NX3−\ce{N^3-}710largest in this set
OX2−\ce{O^2-}810smaller
FX−\ce{F-}910smaller
NaX+\ce{Na+}1110smaller
MgX2+\ce{Mg^2+}1210smaller
AlX3+\ce{Al^3+}1310smallest in this set

Because the electron arrangement is the same, the increasing nuclear charge pulls the same electron cloud more strongly. So the ionic radius decreases:

NX3−\ce{N^3-} > OX2−\ce{O^2-} > FX−\ce{F-} > NaX+\ce{Na+} > MgX2+\ce{Mg^2+} > AlX3+\ce{Al^3+}

Worked example: justifying the smallest isoelectronic ion

Question: Which ion is smaller, NaX+\ce{Na+} or MgX2+\ce{Mg^2+}?

Both ions have 10 electrons and the same electron arrangement, 2,8. Magnesium has 12 protons, while sodium has 11 protons. The MgX2+\ce{Mg^2+} nucleus attracts the same number of electrons more strongly, so MgX2+\ce{Mg^2+} has the smaller ionic radius.

Physical Properties As Evidence For Ions

The ionic model is useful because it explains evidence. A substance that contains mobile charged particles conducts electricity. A substance with charged particles locked into fixed positions does not conduct, even though charges are present.

In a solid ionic lattice, ions vibrate about fixed positions. They are charged, but they are not free to move through the structure. Solid sodium chloride does not conduct electricity because there are no mobile charge carriers.

When an ionic compound is molten or dissolved in water, the ions can move. The mobile ions carry charge through the liquid, so the melt or solution conducts electricity. This is strong evidence that the compound contains charged particles rather than neutral molecules.

[DIAGRAM: asset_name: Ionic Lattice Mobile Ions; asset_slug: edexcel_a_level_chemistry_l008_ionic_lattice_mobile_ions; recommended_method: matplotlib; description: Pale-colour schematic comparing fixed alternating ions in a solid lattice with mobile positive and negative ions moving toward opposite electrodes in a molten or aqueous ionic compound.]
Diagram

High melting temperatures are also evidence for strong attractions in a giant ionic lattice. A large amount of energy is needed to overcome enough electrostatic attraction for the lattice to lose its fixed structure. This does not mean covalent bonds inside molecules are being broken; in an ionic lattice, the relevant attractions are between ions throughout the structure.

Worked example: explaining conductivity

A student says: "Sodium chloride contains charged ions, so solid sodium chloride should conduct electricity."

The first clause is right, but the conclusion is wrong. Solid sodium chloride contains ions, but they are fixed in the lattice and cannot move through the solid. Molten sodium chloride conducts because the ions are mobile and can carry charge.

Migration Of Ions

Ion migration gives more direct evidence than conductivity alone. If an electric field is applied across a solution containing coloured ions, positive ions move towards the negative electrode and negative ions move towards the positive electrode. The direction of movement reveals the charge on the particles.

Coloured-ion demonstrations make the movement visible. Use separate demonstrations for a suitable coloured cation and an anion: a blue copper(II) ion moves towards the negative electrode, while a purple manganate(VII) ion, MnOX4X−\ce{MnO4-}, moves towards the positive electrode. Separate demonstrations avoid assuming that any two coloured ions form a soluble mixture. On electrolyte-wetted filter paper, mark the starting spot and electrode polarities, apply a low-voltage direct-current supply and record how the coloured region moves with time. Compare with a no-voltage control: diffusion spreads a spot, whereas directed movement reverses when electrode polarity reverses. This is evidence for the sign of the moving charge.

This is why "conducts when molten" and "ions migrate under a potential difference" are evidence statements, not just property statements. They show that the charge carriers are ions that can move when the lattice is disrupted or when the substance is in solution.

Reasoning shape

For an explain question, build the answer in this order:

  1. Name the structure or particles: giant ionic lattice / positive and negative ions.
  2. State the relevant movement: fixed ions in a solid, mobile ions in a melt or solution.
  3. Link movement to evidence: mobile charged ions conduct or migrate to oppositely charged electrodes.
  4. Use charge/radius language only if the question asks about strength, melting temperature, or a comparison.

That order keeps the cause-and-effect visible. It also prevents a common error: writing "free electrons" for an ionic melt. Free electrons are not the charge carriers in molten sodium chloride; mobile ions are.

[DIAGRAM: asset_name: Directed Ion Migration; asset_slug: edexcel_a_level_chemistry_l008_directed_migration; recommended_method: matplotlib; description: Separate wetted-paper demonstrations show a blue cation moving towards the negative electrode and purple anion towards the positive electrode, relative to marked starting positions.]
Diagram