N1, N2 - Integers, decimals and written arithmetic

N1, N2 - Integers, decimals and written arithmetic

Compare positive and negative numbers, understand what each digit is worth, and calculate with integers and decimals. Written methods and simple checks will help you spot an answer with the wrong sign or size.

Ordering numbers and comparison symbols

Which is warmer: −0.5 °C-0.5\,\mathrm{°C} or −0.57 °C-0.57\,\mathrm{°C}? The digits alone can tempt you into the wrong answer. Their positions on a number line settle it.

An integer is a whole number, including zero and negative whole numbers. A decimal can lie between integers: −2.4-2.4 is between −3-3 and −2-2. Numbers increase to the right. Thus −8<−3-8 < -3, even though −8-8 is farther from zero. Distance from zero and numerical order are different ideas.

[DIAGRAM: asset_name: Signed numbers on a number line; asset_slug: 1ma1_m01_signed_order; caption: Numbers farther right are greater, including negative decimals.; description: A number line from minus 4 to 2 marks minus 3.2, minus 1.5, zero and 0.8 in increasing order, with an arrow showing that values increase to the right.]
Numbers farther right are greater, including negative decimals.

Use these symbols to express the comparison precisely.

Comparison symbols

== means equal to; ≠\ne means not equal to; << means less than; >> means greater than; ≤\le means less than or equal to; ≥\ge means greater than or equal to.

For example, 0.50=0.50.50 = 0.5, 3≠−33 \ne -3 and −4<−1-4 < -1. The statement x≤5x \le 5 allows x=5x = 5; x<5x < 5 does not.

The open end of an inequality faces the larger value. Reversing the numbers reverses the sign: −4<−1-4 < -1 and −1>−4-1 > -4 say the same thing. To compare positive decimals, align decimal points and use trailing zeros to make the columns visible.

Worked example 1: ordering positive decimals

Question. Write 0.50.5, 0.570.57 and 0.5070.507 in increasing order.

Plan. Write each value to three decimal places, then compare the first different column.

0.5=0.500trailing zeros preserve value0.57=0.570align the decimal columns0.500<0.507<0.570compare hundredths, then thousandths\begin{aligned} 0.5 &= 0.500 && \text{trailing zeros preserve value} \\ 0.57 &= 0.570 && \text{align the decimal columns} \\ 0.500 &< 0.507 < 0.570 && \text{compare hundredths, then thousandths} \end{aligned}

Why this step? Equal-length decimal forms let you compare the same place values, rather than counting digits.

Answer. 0.5, 0.507, 0.570.5,\ 0.507,\ 0.57.

Check. All three are between 0.50.5 and 0.60.6; the extra 77 thousandths makes 0.5070.507 just greater than 0.50.5.

Now change only the signs. The positive magnitudes have the same order, but the negative values lie to the left of zero.

Worked example 2: ordering the negative versions

Question. Write −0.5-0.5, −0.57-0.57 and −0.507-0.507 in increasing order.

Plan. Compare the positive magnitudes, then reverse their order.

0.500<0.507<0.570compare positive magnitudes−0.570<−0.507<−0.500farther left means smaller\begin{aligned} 0.500 &< 0.507 < 0.570 && \text{compare positive magnitudes} \\ -0.570 &< -0.507 < -0.500 && \text{farther left means smaller} \end{aligned}

Why reverse the order? The greatest positive distance becomes the farthest position to the left when its sign is negative.

Answer. −0.57, −0.507, −0.5-0.57,\ -0.507,\ -0.5.

Check. Starting at −0.57-0.57, moving right reaches −0.507-0.507, then −0.5-0.5, then zero.

A longer decimal need not be larger: there is even no greatest decimal below 11. Given any number d<1d < 1, its midpoint with 11 is larger than dd but still below 11.

Watch out

Wrong: −0.57>−0.5-0.57 > -0.5 because 57>557 > 5. Right: −0.57<−0.50-0.57 < -0.50. Compare place values and then account for the negative signs.

Try the same comparison with a different final digit in one value.

The value of a digit

A digit's position tells you its contribution to the number. Each move one column left makes that contribution ten times as large; each move right divides it by ten.

In 4,072,3054{,}072{,}305, the 44 contributes four million, the 77 contributes seventy thousand and the 33 contributes three hundred. Zeros hold empty places. Removing the zero between 44 and 77 would change the value. Commas group digits for reading; they do not change the number.

Place value

Place value is the value given to a digit by its position. To the right of units come tenths, hundredths, thousandths, ten-thousandths and hundred-thousandths.

For example, 23.047=20+3+4100+7100023.047 = 20 + 3 + \frac{4}{100} + \frac{7}{1000}. The 44 is worth 0.040.04, not 44.

The first column after the decimal point is always tenths. In 0.000620.00062, the 66 is in the ten-thousandths column, so its value is 0.00060.0006.

UnitsTenthsHundredthsThousandthsTen-thousandthsHundred-thousandths
000000006622

Scaling changes the values of all the digits together.

Worked example 3: scaling a small decimal

Question. Work out 0.00062×10000.00062 \times 1000.

Plan. Move each digit three place-value columns left.

0.00062=62100000count hundred-thousandths0.00062×1000=62000100000multiply the quantity=62100=0.62simplify\begin{aligned} 0.00062 &= \frac{62}{100000} && \text{count hundred-thousandths} \\ 0.00062 \times 1000 &= \frac{62000}{100000} && \text{multiply the quantity} \\ &= \frac{62}{100} = 0.62 && \text{simplify} \end{aligned}

Why three columns? 1000=10×10×101000 = 10 \times 10 \times 10, so every digit's contribution is multiplied by ten three times.

Answer. 0.620.62.

Check. 0.62÷1000=0.000620.62 \div 1000 = 0.00062, which reverses the scaling.

Change only multiplication to division. The digits move in the opposite direction.

Worked example 4: dividing the same decimal

Question. Work out 0.00062÷10000.00062 \div 1000.

Plan. Divide each digit's contribution by 10001000.

0.00062÷1000=62100000×1000divide the quantity=62100000000multiply the denominators=0.00000062write the decimal\begin{aligned} 0.00062 \div 1000 &= \frac{62}{100000 \times 1000} && \text{divide the quantity} \\ &= \frac{62}{100000000} && \text{multiply the denominators} \\ &= 0.00000062 && \text{write the decimal} \end{aligned}

Why add places on the right? Division makes this positive number smaller; moving digits left would multiply it instead.

Answer. 0.000000620.00000062.

Check. Multiplying the answer by 10001000 recovers 0.000620.00062.

The same reasoning gives 62÷1000=0.06262 \div 1000 = 0.062: six tens become six hundredths and two units become two thousandths.

Watch out

Trailing decimal zeros preserve value: 2.30=2.32.30 = 2.3. Appending a zero to an integer changes its place values: 230=10×23230 = 10 \times 23. Do not treat every zero as removable.

Use the same division with one changed digit.

Written operations and negative integers

Written methods keep units aligned and record exchanges, so you can handle large calculations one small step at a time.

You already know

Ten units make one ten, and ten tens make one hundred. Addition combines quantities; subtraction reverses addition. Multiplication and division are another inverse pair.

For addition, align units under units. In 478+267478 + 267, 8+7=158 + 7 = 15: write 55 units and carry 11 ten. Then 7+6+1=147 + 6 + 1 = 14: write 44 tens and carry 11 hundred. Finally 4+2+1=74 + 2 + 1 = 7, giving 745745.

For 602−278602 - 278, exchange a hundred for ten tens, then one ten for ten units. This preserves the value of 602602:

602=500+90+12exchange across the zero602−278=(500−200)+(90−70)+(12−8)subtract matching places=300+20+4=324combine the results\begin{aligned} 602 &= 500 + 90 + 12 && \text{exchange across the zero} \\ 602 - 278 &= (500 - 200) + (90 - 70) + (12 - 8) && \text{subtract matching places} \\ &= 300 + 20 + 4 = 324 && \text{combine the results} \end{aligned}

The inverse check is 324+278=602324 + 278 = 602. For signed addition, moving right adds a positive value and moving left adds a negative value. Thus −7+12=5-7 + 12 = 5 and −7+(−12)=−19-7 + (-12) = -19. Subtracting a negative reverses that leftward move: −7−(−12)=−7+12=5-7 - (-12) = -7 + 12 = 5.

For multiplication or division, matching signs give a positive answer and different signs give a negative answer. Work out the magnitude first.

Worked example 5: long multiplication

Question. Work out 326×24326 \times 24 without a calculator.

Plan. Multiply by the units and tens separately, then add the partial products.

326×4=1304units row326×20=6520tens row326×24=1304+6520=7824combine both rows\begin{aligned} 326 \times 4 &= 1304 && \text{units row} \\ 326 \times 20 &= 6520 && \text{tens row} \\ 326 \times 24 &= 1304 + 6520 = 7824 && \text{combine both rows} \end{aligned}

For the units row, 4×6=244 \times 6 = 24: write 44, carry 22. Next 4×2+2=104 \times 2 + 2 = 10: write 00, carry 11. Finally 4×3+1=134 \times 3 + 1 = 13.

Why 2020, rather than 22? The 22 in 2424 is in the tens column; its row must be ten times 326×2326 \times 2.

Answer. 78247824.

Check. 300×24=7200300 \times 24 = 7200 and 26×24=62426 \times 24 = 624; their sum is 78247824.

Change only the sign of the first factor. The written multiplication is unchanged.

Worked example 6: applying a negative sign

Question. Work out (−326)×24(-326) \times 24.

Plan. Calculate the positive magnitude, then use the different-sign rule.

326×24=1304+6520=7824use both partial products(−326)×24=−7824different signs\begin{aligned} 326 \times 24 &= 1304 + 6520 = 7824 && \text{use both partial products} \\ (-326) \times 24 &= -7824 && \text{different signs} \end{aligned}

Why is the result negative? Twenty-four copies of a negative quantity have a negative total.

Answer. −7824-7824.

Check. (−7824)÷24=−326(-7824) \div 24 = -326, reversing the multiplication.

Long division uses the same place values. To find 936÷24936 \div 24, 2424 goes into 9393 three times. Write 33 in the tens column and subtract 7272, leaving 2121 tens. Bring down 66 to make 216216. Nine lots of 2424 give 216216, so the quotient is 3939. Check 39×24=93639 \times 24 = 936. Therefore (−936)÷(−24)=39(-936) \div (-24) = 39 too.

With a positive divisor, a remainder must be at least zero and less than the divisor. You can continue into decimal places when appropriate. Division by zero is undefined: for example, no number multiplied by zero gives 55.

Watch out

“Two negatives make a positive” applies to multiplication and division. It does not apply to addition: (−7)+(−12)=−19(-7) + (-12) = -19, whereas (−7)×(−12)=84(-7) \times (-12) = 84.

Change the magnitude of the negative factor and keep the multiplication method.

Calculating with decimals

Decimal calculations use integer methods once you keep track of each digit's place value.

For addition and subtraction, align decimal points. Write 12.7+0.8612.7 + 0.86 as 12.70+0.86=13.5612.70 + 0.86 = 13.56. Similarly, 5.2−1.87=5.20−1.87=3.335.2 - 1.87 = 5.20 - 1.87 = 3.33. The added zeros allow exchanges in the hundredths column. Adding less than one to 12.712.7 cannot produce a result near 2121.

For multiplication, first use integers, then restore the scale. For division, scale both numbers by the same power of ten until the divisor is an integer. These rules are not on the formula sheet; learn them through place value.

Worked example 7: multiplying decimals

Question. Work out 2.4×0.352.4 \times 0.35 without a calculator.

Plan. Multiply 2424 by 3535, then divide by the combined scale factor.

24×35=120+720=840units and tens products2.4×0.35=24×3510×100restore both scales=8401000=0.84divide by 1000\begin{aligned} 24 \times 35 &= 120 + 720 = 840 && \text{units and tens products} \\ 2.4 \times 0.35 &= \frac{24 \times 35}{10 \times 100} && \text{restore both scales} \\ &= \frac{840}{1000} = 0.84 && \text{divide by }1000 \end{aligned}

Why divide by 10001000? Replacing 2.42.4 by 2424 multiplies one factor by 1010; replacing 0.350.35 by 3535 multiplies the other by 100100.

Answer. 0.840.84.

Check. 0.350.35 is between 0.30.3 and 0.40.4, so the product is between 0.720.72 and 0.960.96. It is smaller than 2.42.4, as multiplying by a positive number below one should be.

Change only the sign of 2.42.4. The scale and positive magnitude stay the same.

Worked example 8: a signed decimal product

Question. Work out (−2.4)×0.35(-2.4) \times 0.35.

Plan. Use the integer product, restore its scale, then choose the sign.

24×35=840calculate the magnitude8401000=0.84restore three decimal places(−2.4)×0.35=−0.84different signs\begin{aligned} 24 \times 35 &= 840 && \text{calculate the magnitude} \\ \frac{840}{1000} &= 0.84 && \text{restore three decimal places} \\ (-2.4) \times 0.35 &= -0.84 && \text{different signs} \end{aligned}

Why keep the sign separate? The sign rule and the decimal scale are two different decisions; checking each prevents one from hiding an error in the other.

Answer. −0.84-0.84.

Check. (−0.84)÷0.35=−2.4(-0.84) \div 0.35 = -2.4. If both factors were negative, the result would instead be 0.840.84.

For division, 6.84÷0.3=68.4÷3=22.86.84 \div 0.3 = 68.4 \div 3 = 22.8. Multiplying both numbers by 1010 preserves their ratio. Multiplying just one would change it. Check 22.8×0.3=6.8422.8 \times 0.3 = 6.84; changing the dividend to −6.84-6.84 gives quotient −22.8-22.8.

When the divisor is already whole, keep the quotient's decimal point aligned with the dividend's. For 7.35÷57.35 \div 5, divide 77 units to get 11 unit with 22 left. The remainder and 33 tenths make 2323 tenths: divide to get 44 tenths with 33 tenths left. Together with 55 hundredths this is 3535 hundredths, giving 77 hundredths. The result is 1.471.47, and 1.47×5=7.351.47 \times 5 = 7.35.

Watch out

Wrong: 6.84÷0.3=6.84÷36.84 \div 0.3 = 6.84 \div 3. Right: 6.84÷0.3=68.4÷36.84 \div 0.3 = 68.4 \div 3. Scale the dividend and divisor together.

The next product changes only the magnitude of the negative factor in the second example.

Quick Recap

  • Compare place values first; negative values farther left are smaller.
  • The six comparison symbols distinguish equality, inequality and whether equality is allowed.
  • Written arithmetic aligns like places and records exchanges or partial products.
  • Decimal multiplication restores both scales; decimal division scales both inputs together.
  • Inverse operations and rough size checks help catch sign and place-value errors.

The warmer temperature is −0.5 °C-0.5\,\mathrm{°C}, because −0.5>−0.57-0.5 > -0.57.