2.1 - Hyperbolic functions and graphs

2.1 - Hyperbolic functions and graphs

A small change from adding exponentials to subtracting them produces two very different curves. You will define the six hyperbolic functions, build their graphs from their formulae, and solve equations while keeping track of the real values each function can take.

Exponential definitions

How can two functions made from the same exponentials behave so differently that one reaches every real height, while the other never falls below 11? Start with eln⁡3=3e^{\ln 3}=3 and e−ln⁡3=1/3e^{-\ln 3}=1/3: their half-sum is 5/35/3, but their half-difference is 4/34/3.

The names hyperbolic sine and hyperbolic cosine refer to these half-difference and half-sum functions. The argument is a real number; the definitions use exponentials directly.

The six hyperbolic functions

For real xx,

sinh⁡x=ex−e−x2,cosh⁡x=ex+e−x2,\sinh x=\frac{e^x-e^{-x}}2, \qquad \cosh x=\frac{e^x+e^{-x}}2, tanh⁡x=sinh⁡xcosh⁡x=ex−e−xex+e−x,sech⁡x=1cosh⁡x=2ex+e−x.\tanh x=\frac{\sinh x}{\cosh x} =\frac{e^x-e^{-x}}{e^x+e^{-x}}, \qquad \operatorname{sech}x=\frac1{\cosh x} =\frac2{e^x+e^{-x}}.

For real x≠0x\ne0,

cosech⁡x=1sinh⁡x=2ex−e−x,coth⁡x=cosh⁡xsinh⁡x=ex+e−xex−e−x.\operatorname{cosech}x=\frac1{\sinh x} =\frac2{e^x-e^{-x}}, \qquad \coth x=\frac{\cosh x}{\sinh x} =\frac{e^x+e^{-x}}{e^x-e^{-x}}.

The exponential definitions are not in the formula booklet: learn them.

The exclusions come from the denominators. The sum ex+e−xe^x+e^{-x} is always positive. The difference is zero exactly when e2x=1e^{2x}=1, which means x=0x=0. Thus tanh⁡0=0\tanh 0=0 and sech⁡0=1\operatorname{sech}0=1, while cosech⁡0\operatorname{cosech}0 and coth⁡0\coth0 are undefined.

Worked example 1: exact values at a positive argument

Question. Find the exact values of all six hyperbolic functions at x=ln⁡3x=\ln3.

Plan. Find sinh⁡x\sinh x and cosh⁡x\cosh x from the exponentials, then take their ratios and reciprocals.

Since ex=3e^x=3 and e−x=1/3e^{-x}=1/3,

sinh⁡x=3−1/32=43,cosh⁡x=3+1/32=53.\sinh x=\frac{3-1/3}{2}=\frac43, \qquad \cosh x=\frac{3+1/3}{2}=\frac53.

Therefore

tanh⁡x=4/35/3=45,sech⁡x=35,\tanh x=\frac{4/3}{5/3}=\frac45, \qquad \operatorname{sech}x=\frac35, cosech⁡x=34,coth⁡x=5/34/3=54.\operatorname{cosech}x=\frac34, \qquad \coth x=\frac{5/3}{4/3}=\frac54.

Answer. In the order sinh⁡,cosh⁡,tanh⁡,sech⁡,cosech⁡,coth⁡\sinh,\cosh,\tanh,\operatorname{sech},\operatorname{cosech},\coth, the values are 4/3,5/3,4/5,3/5,3/4,5/44/3,5/3,4/5,3/5,3/4,5/4.

Check. Evaluate the last four directly from ex=3e^x=3: for example, tanh⁡x=(9−1)/(9+1)=4/5\tanh x=(9-1)/(9+1)=4/5 and coth⁡x=(9+1)/(9−1)=5/4\coth x=(9+1)/(9-1)=5/4. Their product is 11, as the reciprocal definitions require.

Change only the sign of the argument. This swaps exe^x and e−xe^{-x}, so the sum stays the same and the difference changes sign.

Worked example 2: reversing the argument

Question. Find the exact values of all six hyperbolic functions at x=−ln⁡3x=-\ln3.

Plan. Substitute ex=1/3e^x=1/3 and e−x=3e^{-x}=3, then form the same ratios.

sinh⁡x=1/3−32=−43,cosh⁡x=1/3+32=53.\sinh x=\frac{1/3-3}{2}=-\frac43, \qquad \cosh x=\frac{1/3+3}{2}=\frac53.

Hence

tanh⁡x=−45,sech⁡x=35,cosech⁡x=−34,coth⁡x=−54.\tanh x=-\frac45, \qquad \operatorname{sech}x=\frac35, \qquad \operatorname{cosech}x=-\frac34, \qquad \coth x=-\frac54.

Answer. The four functions sinh⁡,tanh⁡,cosech⁡,coth⁡\sinh,\tanh,\operatorname{cosech},\coth change sign; cosh⁡\cosh and sech⁡\operatorname{sech} keep their values.

Check. Direct substitution into the exponential forms gives sech⁡x=2/(1/3+3)=3/5\operatorname{sech}x=2/(1/3+3)=3/5 and cosech⁡x=2/(1/3−3)=−3/4\operatorname{cosech}x=2/(1/3-3)=-3/4, agreeing with the reciprocal calculation.

These sign rules hold for every allowed argument, not just logarithms. A function with f(−x)=f(x)f(-x)=f(x) is even; one with f(−x)=−f(x)f(-x)=-f(x) is odd. They will let us construct half a graph and reflect it.

Watch out

sech⁡x\operatorname{sech}x means 1/cosh⁡x1/\cosh x. It does not mean cosh⁡(1/x)\cosh(1/x). In particular, sech⁡0\operatorname{sech}0 exists and equals 11.

Use the definitions with a different logarithm.

Shapes and domains

The exponential definitions determine each graph's symmetry, intercepts and behaviour far from the origin. Unlike their trigonometric namesakes, these six real functions are not periodic.

For sinh⁡x\sinh x, increasing xx increases both exe^x and −e−x-e^{-x}, so the half-difference increases throughout the real line. It passes through the origin and is unbounded in both directions. For cosh⁡x\cosh x, write

cosh⁡x−1=(ex/2−e−x/2)22≥0.\cosh x-1=\frac{(e^{x/2}-e^{-x/2})^2}{2}\ge0.

Equality occurs only at x=0x=0. Its even graph therefore has a minimum at (0,1)(0,1), with both ends rising without bound.

To see the limiting heights of tanh⁡x\tanh x, divide numerator and denominator by exe^x:

tanh⁡x=1−e−2x1+e−2x⟶1as x⟶∞.\tanh x=\frac{1-e^{-2x}}{1+e^{-2x}}\longrightarrow1 \quad\text{as }x\longrightarrow\infty.

Odd symmetry gives the limit −1-1 at the other end. Also, tanh⁡x=1−2/(e2x+1)\tanh x=1-2/(e^{2x}+1): as xx increases, the subtracted positive fraction decreases, so tanh increases. The graph never reaches either limiting height: the positive denominator is always larger than the magnitude of the numerator.

[DIAGRAM: asset_name: The three basic hyperbolic graphs; asset_slug: cam9231-hyperbolic-basic; caption: Sinh is unbounded, cosh has minimum 1, and tanh approaches two horizontal asymptotes; description: Three exact coordinate plots of sinh x, cosh x and tanh x. Sinh crosses the origin with odd symmetry. Cosh has even symmetry and a marked minimum at zero comma one. Tanh is odd and lies strictly between dashed horizontal lines y equals minus one and y equals one.]
Sinh is unbounded, cosh has minimum 1, and tanh approaches two horizontal asymptotes

Taking reciprocals gives the remaining graphs. A positive quantity growing without bound has a reciprocal approaching zero. A quantity approaching zero from above or below has a reciprocal growing without bound with the same sign. In particular, the zero of sinh⁡x\sinh x creates a vertical asymptote for both cosech⁡x\operatorname{cosech}x and coth⁡x\coth x.

[DIAGRAM: asset_name: Reciprocal hyperbolic graphs; asset_slug: cam9231-hyperbolic-reciprocals; caption: Sech has maximum 1, while cosech and coth exclude zero and have two branches; description: Three exact coordinate plots of sech x, cosech x and coth x. Sech is even with maximum zero comma one and tends to zero at both ends. Cosech is odd with vertical asymptote x equals zero and horizontal asymptote y equals zero. Coth is odd with vertical asymptote x equals zero and horizontal asymptotes y equals minus one and y equals one.]
Sech has maximum 1, while cosech and coth exclude zero and have two branches

Here is the full set of features needed for sketches. A horizontal asymptote records a limit; it is not automatically part of the range.

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