3.1.3 - Estimation of Physical Quantities

3.1.3 - Estimation of Physical Quantities

Physicists routinely need to judge whether a calculated answer is reasonable, compare the scales of different phenomena, or make quick predictions without precise data. This lesson develops your ability to work with orders of magnitude and to produce sensible estimates of physical quantities and derived quantities.

Part 1 — Orders of Magnitude

An order of magnitude is a way of expressing the approximate size of a quantity using powers of ten. Rather than quoting an exact value, we round to the nearest power of ten to capture the overall scale.

Order of Magnitude

The order of magnitude of a quantity is the power of ten closest to its value. It is used to express or compare the scale of physical quantities.

For example, the diameter of an atomic nucleus is approximately 101510^{-15} m, while the diameter of an atom is approximately 101010^{-10} m. We say the atom is five orders of magnitude larger than the nucleus because it is roughly 10510^5 times bigger.

To find the order of magnitude of a number, first write it in standard form as a×10na \times 10^n, where 1a<101 \leq a < 10. On a logarithmic scale the boundary between 10n10^n and 10n+110^{n+1} is 10×10n\sqrt{10} \times 10^n. Therefore, if a<103.16a < \sqrt{10} \approx 3.16, the order of magnitude is 10n10^n; if a10a \geq \sqrt{10}, it is 10n+110^{n+1}.

For instance, the speed of light is 3.0×1083.0 \times 10^8 m s1^{-1}, so its order of magnitude is 10810^8 m s1^{-1}. A value of 7.2×1047.2 \times 10^4 has order of magnitude 10510^5 because 7.27.2 is closer to 1010 than to 11.

The table below gives some important orders of magnitude that are useful reference points across physics:

QuantityApproximate ValueOrder of Magnitude
Diameter of a proton1015\sim 10^{-15} m101510^{-15} m
Diameter of an atom1010\sim 10^{-10} m101010^{-10} m
Thickness of a sheet of paper104\sim 10^{-4} m10410^{-4} m
Height of a person2\sim 2 m10010^{0} m
Diameter of the Earth107\sim 10^{7} m10710^{7} m
Distance to the Sun1011\sim 10^{11} m101110^{11} m
Mass of an electron1030\sim 10^{-30} kg103010^{-30} kg
Mass of a person102\sim 10^{2} kg10210^{2} kg
Mass of the Earth6×1024\sim 6 \times 10^{24} kg102510^{25} kg

Being familiar with values like these makes it much easier to decide whether an estimate is sensible before you trust a detailed calculation.

Part 2 — Estimation as a Skill

Estimation

Estimation is the process of making an approximate calculation or judgement of a physical quantity using reasonable assumptions, sensible rounding, and known reference values, typically to the nearest order of magnitude.

Estimation is not guessing. It is a structured process in which you identify the relevant physics, choose sensible approximate values, calculate with simplified numbers, and then round the result to the nearest power of ten.

The key is that each assumption must be physically reasonable. Estimating the height of a door as 2 m is sensible. Estimating it as 20 m is not. Good estimates are built from experience, known physical values, and equations you already trust. A useful routine is to follow the same sequence each time: identify the quantity, choose a relevant equation, estimate the inputs with sensible assumptions, calculate, and then round the final answer to the nearest order of magnitude.

Checking calculator results is one of the most useful applications of estimation. If a detailed calculation gives the density of a metal cylinder as 25302530 kg m3^{-3}, you can quickly estimate the volume and confirm that a density of order 10310^3 kg m3^{-3} is plausible rather than wildly wrong.

Part 3 — Worked Examples: Direct Estimates

Direct estimates use approximate measurements of one quantity to estimate another quantity of the same object, such as an area or a volume.

Worked Example 1: Area of a hydrogen atom

The diameter of a hydrogen atom is approximately 1.06×10101.06 \times 10^{-10} m. Estimate the cross-sectional area of the atom to the nearest order of magnitude, assuming it is spherical.

Area of a Circle

A=πr2A = \pi r^2

Here AA is the area and rr is the radius of the circular cross-section. The radius is half the diameter, so r=5.3×1011r = 5.3 \times 10^{-11} m.

Substituting gives

A=π×(5.3×1011)2=π×2.81×10218.8×1021 m2A = \pi \times (5.3 \times 10^{-11})^2 = \pi \times 2.81 \times 10^{-21} \approx 8.8 \times 10^{-21} \text{ m}^2

Since 8.8>108.8 > \sqrt{10}, the nearest order of magnitude is 102010^{-20} m2^2.

Worked Example 2: Volume of the Earth

The diameter of the Earth is approximately 1.3×1071.3 \times 10^7 m. Estimate the volume of the Earth to the nearest order of magnitude.

Volume of a Sphere

V=43πr3V = \frac{4}{3}\pi r^3

Here VV is the volume and rr is the radius. The radius is approximately 6.5×1066.5 \times 10^6 m, which is of order 10710^7 m.

Using the rounded value gives

V43π×(107)34×1021 m3V \approx \frac{4}{3}\pi \times (10^7)^3 \approx 4 \times 10^{21} \text{ m}^3

A more careful calculation gives 1.15×10211.15 \times 10^{21} m3^3, so the order of magnitude is still 102110^{21} m3^3.

Round inputs to one significant figure, or directly to a nearby power of ten, before calculating. This keeps the arithmetic manageable while preserving the correct scale of the answer.

Part 4 — Derived Estimates

A derived estimate uses estimated input values together with an equation to calculate a new quantity that was not given directly.

Worked Example 3: Mass of air in a classroom

Estimate the mass of air in a typical classroom.

Start by estimating the dimensions: length 10\approx 10 m, width 8\approx 8 m, and height 3\approx 3 m. This gives a classroom volume of about 240240 m3^3, which is of order 10210^2 m3^3.

Mass from Density and Volume

m=ρVm = \rho V

Here mm is the mass, ρ\rho is the density, and VV is the volume. Taking the density of air as about 11 kg m3^{-3} gives

m1×240=240 kgm \approx 1 \times 240 = 240 \text{ kg}

So the mass of air in the room has order of magnitude 10210^2 kg. Estimation often reveals results that feel surprising at first, which is one reason it is such a good reality check.

This sort of estimate is useful because it links a familiar everyday process to a surprisingly large total, showing how quickly repeated small events accumulate.

Engineers use this kind of back-of-the-envelope reasoning before doing a full design calculation. A quick estimate of the energy available in the wind, or the mass of material needed for a structure, can show whether a design idea is realistic before time is spent refining it.

Part 5 — Comparing Orders of Magnitude

Sometimes the important result is not the value itself but how many orders of magnitude separate two quantities.

Comparing Orders of Magnitude

difference in orders of magnitude=log10 ⁣(AB)\text{difference in orders of magnitude} = \log_{10}\!\left(\frac{A}{B}\right)

In practice, it is often quicker to write both quantities as powers of ten and subtract the exponents. For example, the mass of the Earth is of order 102510^{25} kg and the mass of a person is of order 10210^2 kg, so the Earth is about 23 orders of magnitude more massive.

The logarithmic scale below helps you see what "orders of magnitude apart" means in practice: notice that equal spacing represents multiplying by ten each step, not adding a fixed amount.

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Diagram

Being comfortable moving between very large and very small scales is a hallmark of physical thinking. Estimation gives you a way to navigate that range without needing exact data for every step.