8B - Dividing a line in a ratio

8B - Dividing a line in a ratio

How can you locate a point one-third of the way along a sloping segment without measuring the diagram? You will find midpoints, divide segments in a stated ratio and work backwards to find a missing endpoint or ratio.

Midpoints

Where is the halfway point between (−3,2)(-3,2) and (7,8)(7,8)? It must be halfway through both coordinate changes.

The total horizontal change is 1010 and the vertical change is 66. Starting at (−3,2)(-3,2), half those changes take you to (−3+5,2+3)=(2,5)(-3+5,2+3)=(2,5).

Midpoint

The midpoint of a segment is the point on the segment at equal distances from its endpoints.

For one coordinate, starting at x1x_1 and adding half the change gives x1+12(x2−x1)=12(x1+x2)x_1+\tfrac12(x_2-x_1)=\tfrac12(x_1+x_2). The same reasoning applies to the other coordinate.

Midpoint coordinates

The midpoint of A(x1,y1)A(x_1,y_1) and B(x2,y2)B(x_2,y_2) is

M(x1+x22,y1+y22).M\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right).

Not on the formulae sheet: learn it as the equal-ratio case of the division formula.

Average the two xx-coordinates together and the two yy-coordinates together. Do not mix a horizontal coordinate with a vertical one.

Worked example 1: halfway through each change

Question. Find the midpoint of A(−3,2)A(-3,2) and B(7,8)B(7,8).

Plan. Average the coordinates in matching pairs.

xM=−3+72=2average the horizontal positionsyM=2+82=5average the vertical positions\begin{aligned} x_M&=\frac{-3+7}{2}=2 &&\text{average the horizontal positions}\\ y_M&=\frac{2+8}{2}=5 &&\text{average the vertical positions} \end{aligned}

Answer. M=(2,5)M=(2,5).

Check. From AA to MM the changes are (5,3)(5,3), and from MM to BB they are also (5,3)(5,3). Thus both half-segments have length 34\sqrt{34}.

Now change one endpoint so that both coordinate sums are odd. A midpoint need not have integer coordinates.

Worked example 2: fractional midpoint coordinates

Question. Find the midpoint of A(−3,2)A(-3,2) and C(8,9)C(8,9).

Plan. Use the same averages and retain exact fractions.

xM=−3+82=52yM=2+92=112\begin{aligned} x_M&=\frac{-3+8}{2}=\frac52\\ y_M&=\frac{2+9}{2}=\frac{11}{2} \end{aligned}

Answer. M=(52,112)M=\left(\tfrac52,\tfrac{11}{2}\right).

Check. Each half of the segment has horizontal change 112\tfrac{11}{2} and vertical change 72\tfrac72, so the two lengths agree.

The formula also works for horizontal and vertical segments: averaging a coordinate that stays constant gives that same constant.

Internal division in a given ratio

A ratio tells you what fraction of the entire segment to travel from the first endpoint.

If AP:PB=1:2AP:PB=1:2, the whole segment contains 33 equal parts, so PP is 13\tfrac13 of the way from AA to BB. It is nearer AA, because APAP is the shorter sublength.

[DIAGRAM: asset_name: One part and two parts along a segment; asset_slug: internal-ratio; caption: AP to PB is 1 to 2, so P is one-third of the way from A to B; description: Equal-scale axes show A at 1 comma 2, P at 5 comma 4 and B at 13 comma 8 on one line. Three equal steps along AB are indicated. The first step AP is pale blue and the two-step PB is pale peach.]
AP to PB is 1 to 2, so P is one-third of the way from A to B

For AP:PB=m:nAP:PB=m:n, with m,n>0m,n>0, travel the fraction mm+n\tfrac{m}{m+n} of each coordinate change. For example,

xP=x1+mm+n(x2−x1)=nx1+mx2m+n.x_P=x_1+\frac{m}{m+n}(x_2-x_1)=\frac{nx_1+mx_2}{m+n}.

The weights look reversed because the starting coordinate contributes to both the starting position and the change.

Internal division coordinates

If the endpoints A(x1,y1)A(x_1,y_1) and B(x2,y2)B(x_2,y_2) are distinct and AP:PB=m:nAP:PB=m:n, where m,n>0m,n>0, then

P(nx1+mx2m+n,ny1+my2m+n).P\left(\frac{nx_1+mx_2}{m+n},\frac{ny_1+my_2}{m+n}\right).

This is internal division: PP lies strictly between AA and BB.

Not on the formulae sheet: learn it.

State the order AP:PBAP:PB before substituting. The coefficient of BB's coordinates is mm, the numerator of the fraction travelled from AA.

Worked example 3: one-third of a segment

Question. A(1,2)A(1,2) and B(13,8)B(13,8) are joined by a segment. Find PP when AP:PB=1:2AP:PB=1:2.

Plan. Travel 13\tfrac13 of each change from AA.

xP=1+13(13−1)=5yP=2+13(8−2)=4\begin{aligned} x_P&=1+\frac13(13-1)=5\\ y_P&=2+\frac13(8-2)=4 \end{aligned}

Answer. P=(5,4)P=(5,4).

Check. The changes from AA to PP are (4,2)(4,2); those from PP to BB are (8,4)(8,4). The second length is twice the first, as required.

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