3.20C-3.22C - Changing equilibrium conditions

3.20C-3.22C - Changing equilibrium conditions

Some reversible reactions do not go fully to reactants or fully to products. Once dynamic equilibrium has been reached, the important question is what happens if a condition changes. This lesson shows how catalysts, temperature and pressure affect the equilibrium mixture, using only the direction rules required for Edexcel International GCSE Chemistry.

Dynamic equilibrium

A reversible reaction at dynamic equilibrium is still reacting in both directions. It only looks steady because the two rates are balanced.

Dynamic equilibrium

Dynamic equilibrium is reached when the forward and reverse reactions occur at the same rate, so the concentrations of reactants and products remain constant.

Dynamic equilibrium can only be maintained in a closed or sealed system, because substances must not escape. If gas leaves the container, the mixture is no longer fixed and the forward and reverse reactions cannot settle into a steady balance.

[DIAGRAM: asset_name: Changing Equilibrium Conditions - diagram 01; asset_slug: c47_changing_equilibrium_conditions__diagram_01; recommended_method: image_gen; description: Monochrome sealed-container diagram for dynamic equilibrium. It shows reactant particles and product particles in one closed container, equal-sized forward and reverse arrows, and steady concentration indicators to emphasise that the forward and reverse reactions happen at the same rate while reactant and product concentrations remain constant.]
Diagram

"Constant concentration" does not mean "equal concentration". At equilibrium, there might be more reactants than products, more products than reactants, or similar amounts of each. The key idea is that the concentrations stop changing because every forward change is matched by a reverse change.

For a reaction written as:

A(g)⇌B(g)A(g) \rightleftharpoons B(g)

dynamic equilibrium means:

  • particles of AA are still forming BB
  • particles of BB are still forming AA
  • the two rates are equal
  • the concentrations of AA and BB stay constant

Catalysts and equilibrium position

A catalyst increases the rate of a reaction. In a reversible reaction, the catalyst provides a faster route for both directions.

At equilibrium, the forward and reverse rates must be equal. A catalyst speeds up the forward reaction and the reverse reaction equally, so it does not favour one side over the other. This means a catalyst does not change the position of equilibrium.

[DIAGRAM: asset_name: Changing Equilibrium Conditions - diagram 02; asset_slug: c47_changing_equilibrium_conditions__diagram_02; recommended_method: deterministic_drawing; description: Monochrome line graph of product concentration against time. A dashed curve labelled with catalyst reaches the equilibrium plateau sooner than a solid curve labelled no catalyst, but both curves finish at the same plateau to show that a catalyst changes rate, not equilibrium position.]
Diagram

The position of equilibrium means the relative amounts of reactants and products in the equilibrium mixture. If the position shifts towards the products, the yield of products increases. If it shifts towards the reactants, the yield of products decreases.

A catalyst can be useful industrially because it helps the mixture reach equilibrium faster. It does not increase the final equilibrium yield.

Changing temperature

Every reversible reaction has one endothermic direction and one exothermic direction. If the forward reaction is endothermic, the reverse reaction is exothermic. If the forward reaction is exothermic, the reverse reaction is endothermic.

Temperature changes shift the position of equilibrium according to this rule:

Change in temperatureEquilibrium shifts in the direction of...
Increase temperaturethe endothermic reaction
Decrease temperaturethe exothermic reaction

Use the enthalpy change sign to decide which direction is endothermic. For the forward reaction:

  • ΔH\Delta H is positive: forward reaction is endothermic
  • ΔH\Delta H is negative: forward reaction is exothermic

For example:

N2O4(g)⇌2NO2(g)ΔH=+57 kJ/molN_2O_4(g) \rightleftharpoons 2NO_2(g) \qquad \Delta H = +57\text{ kJ/mol}

The forward reaction is endothermic. Increasing the temperature shifts equilibrium to the right, towards NO2NO_2. Decreasing the temperature shifts equilibrium to the left, towards N2O4N_2O_4, because the reverse direction is exothermic.

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