3.18-3.19 - Refractive index equation and practical

3.18-3.19 - Refractive index equation and practical

When light enters glass from air at an angle, it changes direction. The refractive index tells you how strongly the glass refracts the light, using the angles measured from the normal. In this lesson you will calculate refractive index from angles, then use a glass-block practical and graph to find a reliable value.

What refractive index means

The normal is an imaginary line drawn at 90∘90^\circ to the surface where the light ray meets the glass. Angles in refraction are measured from the normal, not from the surface.

Refractive index

The refractive index, nn, is a number that describes how much light is refracted when it enters a material from air.

For light travelling from air into glass, the incident ray is in air and the refracted ray is inside the glass. The angle of incidence is ii, and the angle of refraction is rr.

Refractive index

n=sin⁡isin⁡rn = \frac{\sin i}{\sin r}

You must recall this equation: it is not given in the exam, either in this form or rearranged.

The angles are measured in degrees. The sine values are just numbers, so refractive index has no unit. Light slows down when it enters glass, or any other transparent material, from air, so it bends towards the normal: rr is smaller than ii, sin⁡r\sin r is smaller than sin⁡i\sin i, and nn is always greater than 1. For glass, nn is usually around 1.5.

Using the equation

The equation is usually used in one of two ways: calculate nn from measured angles, or calculate one unknown angle when nn is given.

For example, a ray enters a glass block with:

i=45∘andr=28∘i = 45^\circ \quad \text{and} \quad r = 28^\circ

The refractive index is:

n=sin⁡45∘sin⁡28∘n = \frac{\sin 45^\circ}{\sin 28^\circ}

Check that your calculator is in degree mode first. In radian mode, sin⁡45\sin 45 gives 0.851 instead of 0.707, and every answer is wrong.

n=0.7070.469=1.51n = \frac{0.707}{0.469} = 1.51

The answer has no unit. It is sensible for glass because it is close to 1.5.

If nn and ii are known, rearrange before using inverse sine:

n=sin⁡isin⁡rn = \frac{\sin i}{\sin r} sin⁡r=sin⁡in\sin r = \frac{\sin i}{n}

For n=1.50n = 1.50 and i=40∘i = 40^\circ:

sin⁡r=sin⁡40∘1.50=0.429\sin r = \frac{\sin 40^\circ}{1.50} = 0.429 r=sin⁡−1(0.429)=25.4∘r = \sin^{-1}(0.429) = 25.4^\circ

Set the calculator to degree mode. Use inverse sine to recover an angle, not the reciprocal of its sine.

A common error is to put rr and ii the wrong way round. For light going from air into glass, ii should be larger than rr, so n=sin⁡i/sin⁡rn = \sin i / \sin r should give a value greater than 1.

Glass block method

The practical investigates the refractive index of glass by measuring several pairs of ii and rr. The independent variable is the angle of incidence, ii. The dependent variable is the angle of refraction, rr, or the calculated value of sin⁡r\sin r. Keep the same block material, entry face and light colour/source throughout; changing material or wavelength can change the measured index.

[DIAGRAM: asset_name: Refractive index equation and glass block practical - diagram 01; asset_slug: p29_refractive_index_equation_and_practical__diagram_01; recommended_method: image_gen; description: NovaLearn pale-palette ray-box and rectangular-glass-block setup with sage rays at 50° incidence and 31° refraction, parallel 50° emergence, normal-angle arcs i and r, shared entry point and marking crosses.]
Diagram

A strong method is:

  1. Place the glass block on plain white paper and draw around it.
  2. Mark a point on one face where the ray will enter, then draw a normal at 90∘90^\circ to that face.
  3. Replace the block exactly on its outline.
  4. Use a ray box to shine a narrow ray at the entry point at a chosen angle of incidence.
  5. Mark the incident ray and emergent ray with pencil crosses. Keep crosses far apart so the drawn ray direction is more accurate.
  6. Remove the block, join the crosses and extend the incident and emergent lines to its traced outline, then join the entry and exit points: this line is the refracted ray inside the block.
  7. Use a protractor to measure ii and rr from the normal.
  8. Repeat for a range of angles of incidence.

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