3.4 - Dividing a line in a ratio

3.4 - Dividing a line in a ratio

Use equal steps along a straight line to work out a midpoint, a point in a given ratio or a missing endpoint. You will distinguish a point inside a segment from one outside it, so that the ratio and the stated point order select the right answer.

Midpoints and missing endpoints

How can both (4,0)(4,0) and (12,0)(12,0) have distances from A(0,0)A(0,0) and B(6,0)B(6,0) in the ratio 2:12:1? The first has distances 44 and 22; the second has distances 1212 and 66. We will see why “on the line” and “between the points” are different instructions.

Begin with the most familiar ratio, 1:11:1. Half the change in each coordinate takes you halfway along the segment. This is equivalent to averaging the two xx-coordinates and averaging the two yy-coordinates.

Midpoint

The midpoint of a segment ABAB is the point on the segment equally distant from its endpoints. For distinct endpoints, it divides the segment in the ratio AM:MB=1:1AM:MB=1:1. A point merely sharing the same xx-coordinate as the midpoint need not be the midpoint: its yy-coordinate must also be halfway.

Averages work for negative coordinates too. The midpoint between −4-4 and 66 on a number line is −4+12(10)=1-4+\frac12(10)=1, not the average of their positive distances from zero.

Midpoint coordinates

For A(x1,y1)A(x_1,y_1) and B(x2,y2)B(x_2,y_2), the midpoint is

M(x1+x22,y1+y22)M\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)

If AA and MM are known, the missing endpoint is

B(2xM−xA, 2yM−yA)B(2x_M-x_A,\,2y_M-y_A)

Not on the formulae sheet: learn it.

The two questions below use the same halfway relationship in opposite directions.

Worked example 1: averaging both coordinates

Question. Work out the midpoint of A(−4,3)A(-4,3) and B(6,7)B(6,7).

Plan. Average the coordinates separately, keeping each sign.

xM=−4+62=1average the horizontal coordinatesyM=3+72=5average the vertical coordinates\begin{aligned} x_M&=\frac{-4+6}{2}=1 && \text{average the horizontal coordinates}\\ y_M&=\frac{3+7}{2}=5 && \text{average the vertical coordinates} \end{aligned}

Why this step? Halfway along a straight segment means taking half of both coordinate changes at the same time.

Answer. M=(1,5)M=(1,5).

Check. The move from AA to MM is (5,2)(5,2), and the move from MM to BB is also (5,2)(5,2). Equal moves give equal lengths in the same direction.

Worked example 2 changes only which point is unknown. Knowing the midpoint lets you repeat the first half of the journey.

Worked example 2: recovering an endpoint

Question. A(−4,3)A(-4,3) and BB are endpoints of a segment with midpoint M(1,5)M(1,5). Work out the coordinates of BB.

Plan. Make each unknown endpoint coordinate the subject of its midpoint equation.

−4+xB2=1horizontal midpoint conditionxB=2(1)+4=6double and isolate3+yB2=5vertical midpoint conditionyB=2(5)−3=7double and isolate\begin{aligned} \frac{-4+x_B}{2}&=1 && \text{horizontal midpoint condition}\\ x_B&=2(1)+4=6 && \text{double and isolate}\\ \frac{3+y_B}{2}&=5 && \text{vertical midpoint condition}\\ y_B&=2(5)-3=7 && \text{double and isolate} \end{aligned}

Why this step? The midpoint is halfway from the endpoint, not halfway from the origin. Subtracting the known endpoint after doubling accounts for its position.

Answer. B=(6,7)B=(6,7).

Check. From AA to MM is 55 right and 22 up. Repeating that move from MM reaches (6,7)(6,7).

You can recover a missing endpoint by algebra or by equal steps. Both express the same fact, so choose the form that makes your signs clearest.

Watch out

Wrong: double the midpoint to obtain B=(2,10)B=(2,10). This assumes the other endpoint is the origin. Right: B=(2xM−xA,2yM−yA)B=(2x_M-x_A,2y_M-y_A), which gives (6,7)(6,7) here.

Now both halves cross coordinate axes. Keep the subtraction of the known endpoint visible.

Equal steps inside a segment

If PP lies between AA and BB, the ratio AP:PB=m:nAP:PB=m:n divides the whole segment into m+nm+n equal parts.

You already know

In a positive ratio m:nm:n, the total contains m+nm+n equal parts. The first share is mm+n\frac{m}{m+n} of the total, not mn\frac mn. Along one straight line, the same fraction applies to both coordinate changes.

Start at the endpoint named first in the ratio. For AP:PB=2:3AP:PB=2:3, move two of the five equal steps from AA, or three steps backwards from BB. The first route is often easier to keep consistent.

A point inside a segment

For distinct points AA and BB, with PP between them and AP:PB=m:nAP:PB=m:n, where m,n>0m,n>0,

xP=xA+mm+n(xB−xA)yP=yA+mm+n(yB−yA)\begin{aligned} x_P&=x_A+\frac{m}{m+n}(x_B-x_A)\\ y_P&=y_A+\frac{m}{m+n}(y_B-y_A) \end{aligned}

Use signed coordinate changes; the lengths in the ratio are positive.
Not on the formulae sheet: learn it.

Coordinate changes scale together because all the points lie on the same straight segment. You do not divide the absolute coordinates by the ratio entries.

Worked example 3: two parts out of five

Question. A(−2,1)A(-2,1), PP and B(8,6)B(8,6) lie in that order on a straight line. AP:PB=2:3AP:PB=2:3. Work out the coordinates of PP.

Plan. Calculate the whole move from AA to BB, take 25\frac25 of it, then add it to AA.

whole change=(8−(−2),6−1)=(10,5)five equal partsone part=(2,1)divide both changes by 5two parts=(4,2)the move from A to PP=(−2+4,1+2)=(2,3)start at A\begin{aligned} \text{whole change}&=(8-(-2),6-1)=(10,5) && \text{five equal parts}\\ \text{one part}&=(2,1) && \text{divide both changes by }5\\ \text{two parts}&=(4,2) && \text{the move from }A\text{ to }P\\ P&=(-2+4,1+2)=(2,3) && \text{start at }A \end{aligned}

Why this step? The ratio gives a fraction of the change from AA, not a fraction of the final coordinates of BB.

Answer. P=(2,3)P=(2,3).

Check. The moves AP=(4,2)AP=(4,2) and PB=(6,3)PB=(6,3) are respectively 22 and 33 copies of (2,1)(2,1), so their lengths have ratio 2:32:3.

Worked example 4 changes only the unknown: the interior point is known and the second endpoint is missing. Use the number of parts represented by the known move.

Worked example 4: an endpoint from an interior point

Question. A(−2,1)A(-2,1), P(2,3)P(2,3) and BB lie in that order on a straight line. AP:PB=2:3AP:PB=2:3. Work out the coordinates of BB.

Plan. Divide the move from AA to PP by its two parts, then take three more parts from PP.

AP change=(2−(−2),3−1)=(4,2)two parts are knownone part=(2,1)divide by 2PB change=3(2,1)=(6,3)three remaining partsB=(2+6,3+3)=(8,6)continue from P\begin{aligned} AP\text{ change}&=(2-(-2),3-1)=(4,2) && \text{two parts are known}\\ \text{one part}&=(2,1) && \text{divide by }2\\ PB\text{ change}&=3(2,1)=(6,3) && \text{three remaining parts}\\ B&=(2+6,3+3)=(8,6) && \text{continue from }P \end{aligned}

Why this step? The known segment represents 22 parts, not all 55. Dividing it by 55 would make every step too short.

Answer. B=(8,6)B=(8,6).

Check. The whole move is (10,5)(10,5); its first 25\frac25 is (4,2)(4,2), which reaches the given point PP.

Continue this lesson.

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